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alexandr1967 [171]
3 years ago
10

You need to have a password with 55 letters followed by 33 odd digits between 00 and 99, inclusive. if the characters and digits

cannot be used more than once, how many choices do you have for your password?
Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0
Mahtematical and statistical reasoning makes it evident that there is a mistake in the writing of the question and the digits were duplicated. So the right question is:

"You need to have a password with 5 letters followed by 3 odd digits between 0 and 9, inclusive. If the characters and digits cannot be used more than once, how many choices do you have for your passwor?"

The solution is:

5 letters from 26 with no repetition => 26*25*24*23*22 different choices.

odd digits are 1, 3, 5, 7 and 9 => 5 different digits to choose

3 digits from 5 with no repetition => 5*4*3 = 60

Then, the total number of choices is: 26*25*24*23*22*60 = 473,616,000

Answer: 473,616,000 choices.
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expeople1 [14]

Answer:

Y=(\frac{4}{7}) x+2

Step-by-step explanation:

Y=mx+b

M=\frac{x2-x1}{y2-y1}

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M=\frac{-4}{-7}

Y=(\frac{4}{7}) x+2

3 0
3 years ago
What is 6(5−8v)+12=−54
zlopas [31]

Answer: v = 2

Step-by-step explanation:

30-48v+12 = -54

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\frac{-48v}{-48} = \frac{-96}{-48}

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7 0
3 years ago
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John paid $50 for renting a cycle for 5 hours. Which graph shows the relationship between the cost of renting a cycle for differ
SpyIntel [72]

Answer:

Graph A <==

Step-by-step explanation:

$ 50 for 5 hours......50/5 = 10...thats $ 10 per hr

so the equation would be : y = 10x...with x being the number of hrs and y being the total cost.

So ur x axis will be the hours and your y axis will be the total cost.

so ur answer is :the title of the graph is cycle renting. the x axis (the horizontal axis)...since it is the hours, will be labeled 0,1,2,3,4,5,6

the y axis (the vertical axis)...since it is the total cost, will be labeled  

0,10,20,30,40,50,60. points are plotted on (1,10),(2,20), and (3,30)

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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
2 years ago
4. A classmate is having difficulty finding the measures of &lt;BGE and &lt;BDG in the diagram on the right. What mathematical a
Firlakuza [10]
Part 1) Find the measures of angle BGE
we know that
The inscribed angle measures half of the arc it comprises.
so
angle BGE=(1/2)*[arc EB]  

Part 2) Find the angle BDG
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The measure of the external angle is the semi-difference of the arcs that it covers.
so
angle BDG=(1/2)*[arc GEB-arc GB]

8 0
3 years ago
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