<h3>
Answer: approximately 0.19 meters long</h3>
The more accurate value is 0.18982439916059 but this value isn't exact
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Explanation:
The volume of this rectangular block is 0.24*0.19*0.15 = 0.00684 cubic meters.
If we had a cube of this volume, then it has some side length x such that x^3 = 0.00684
Apply the cube root to both sides. This is the same as raising both sides to the 1/3 power
![x^3 = 0.00684\\\\x = \sqrt[3]{0.00684}\\\\x = (0.00684)^{1/3}\\\\x \approx 0.18982439916059\\\\x \approx 0.19\\\\](https://tex.z-dn.net/?f=x%5E3%20%3D%200.00684%5C%5C%5C%5Cx%20%3D%20%5Csqrt%5B3%5D%7B0.00684%7D%5C%5C%5C%5Cx%20%3D%20%280.00684%29%5E%7B1%2F3%7D%5C%5C%5C%5Cx%20%5Capprox%200.18982439916059%5C%5C%5C%5Cx%20%5Capprox%200.19%5C%5C%5C%5C)
The side length of the cube is approximately 0.19 meters long
Answer:
<u>Option b. (x = 3, y = 20, z = -14)</u>
Step-by-step explanation:
Given:
2x + 2y + 3z = 4
5x + 3y + 5z = 5
3x + 4y + 6z = 5
Solve using Cramer’s rule
∴ ![\left[\begin{array}{ccc}2&2&3\\5&3&5\\3&4&6\end{array}\right] =\left[\begin{array}{ccc}4\\5\\5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%262%263%5C%5C5%263%265%5C%5C3%264%266%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C5%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
∴A = ![\left[\begin{array}{ccc}2&2&3\\5&3&5\\3&4&6\end{array}\right] = -1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%262%263%5C%5C5%263%265%5C%5C3%264%266%5Cend%7Barray%7D%5Cright%5D%20%3D%20-1)
Ax = ![\left[\begin{array}{ccc}4&2&3\\5&3&5\\5&4&6\end{array}\right] = -3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%262%263%5C%5C5%263%265%5C%5C5%264%266%5Cend%7Barray%7D%5Cright%5D%20%3D%20-3)
Ay = ![\left[\begin{array}{ccc}2&4&3\\5&5&5\\3&5&6\end{array}\right] =-20\\](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%264%263%5C%5C5%265%265%5C%5C3%265%266%5Cend%7Barray%7D%5Cright%5D%20%3D-20%5C%5C)
Az = ![\left[\begin{array}{ccc}2&2&4\\5&3&5\\3&4&5\end{array}\right] = 14](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%262%264%5C%5C5%263%265%5C%5C3%264%265%5Cend%7Barray%7D%5Cright%5D%20%3D%2014)
∴ x = Ax/A = -3/-1 = 3
y = Ay/A = -20/-1 = 20
z = Az/A = 14/-1 = -14
<u>So, the answer is option b. (x = 3, y = 20, z = -14)</u>
Answer: 12.
To solve this problem, let's first solve for x. Thi is easiest done by figuring what QR is in terms of x using two equations, both from different lines.
In the first line:
QR = 15 - 4x.
In the third line:
QR = 13x - 1 - x = 12x - 1.
Now, we have to set these equations equal to each other.
15 - 4x = 12x - 1
15 = 16x - 1
16x = 16
x = 1
Next, we take line three, 13x - 1, and substitute x as 1. The answer is 12.
Answer: To know if a number is repeating it would have this line on top of it, or it would just be repeating. A repeating number is a pattern of numbers that are repeated.
Step-by-step explanation: But 1/4 is not a repeating number, 1/4 is 0.25. This would be a repeating number; 3/9 = 0.333333333...
