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3 years ago

The equation t= 13p + 108 can be used to estimate the cooking time t in

Mathematics

1 answer:

Setler [38]3 years ago

4 0

Answer:

Step-by-step explanation:

(285)=13p+108

177=13p

p= 13.62 lbs

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In the Pacific Ocean, the Philippine Trench is 10.047 kilometers deep. In the Atlantic Ocean the Brazil Basin is 6.119

Goshia [24]

Answer:

The Philippine Trench in the Pacific Ocean is 10.05 kilometers deep. The Brazil Basin in the Atlantic Ocean is 6.12 kilometers deep.

Step-by-step explanation:

4 0

3 years ago

Round to the nearest ten thousandth. I dont get this

ale4655 [162]

Do you still need help?

4 0

3 years ago

Hansika paid $9.25 for 2.8 pounds of pretzels. About how much did she pay for a pound of pretzels?

NeX [460]

Answer: $3.30

Explanation:
You set up a proportion where

9.25 X
------ = -----
2.8 1

Then you cross multiply and see that...
2.8X = 9.25
Then X = 9.25 / 2.8 = 3.30

4 0

3 years ago

Read 2 more answers

Which of the following values is the solution to the equation

Alchen [17]

Answer:

1.) 3

Step-by-step explanation:

Divide each side by -35. Whatever you do to one side of the equation, you must do to the other side.

$\frac{-35x}{-35}$ = $\frac{-105}{-35}$

X = 3

6 0

3 years ago

Integrate sin^-1(x) dx please explain how to do it aswell ...?

Lynna [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2264253

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx\qquad\quad\checkmark}$

Trigonometric substitution:

$\mathsf{\theta=sin^{-1}(x)\qquad\qquad\dfrac{\pi}{2}\le \theta\le \dfrac{\pi}{2}}$

then,

$\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}$

So the integral $\mathsf{(ii)}$ becomes

$\mathsf{=\displaystyle\int\! \theta\,cos\,\theta\,d\theta\qquad\quad(ii)}$

Integrate $\mathsf{(ii)}$ by parts:

$\begin{array}{lcl} \mathsf{u=\theta}&\quad\Rightarrow\quad&\mathsf{du=d\theta}\\\\ \mathsf{dv=cos\,\theta\,d\theta}&\quad\Leftarrow\quad&\mathsf{v=sin\,\theta} \end{array}\\\\\\\\ \mathsf{\displaystyle\int\!u\,dv=u\cdot v-\int\!v\,du}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-\int\!sin\,\theta\,d\theta}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-(-cos\,\theta)+C}$

$\mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta+cos\,\theta+C}$

Substitute back for the variable x, and you get

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=sin^{-1}(x)\cdot x+\sqrt{1-x^2}+C}\\\\\\\\ \therefore~~\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=x\cdot\,sin^{-1}(x)+\sqrt{1-x^2}+C\qquad\quad\checkmark}$

I hope this helps. =)

Tags: integral inverse sine function angle arcsin sine sin trigonometric trig substitution differential integral calculus

6 0

3 years ago