Answer:
8. 504ft²
9. 4970yd² (rounded to 3 s.f.)
Formulas (For easy reference):
Area of rectangle = length × breadth
Area of circle = pi×r×r
Circumference of circle = pi×r×2
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Step-by-step explanation:
8. You know a box has 6 sides, and there are 3 types of surfaces that are different from each other, and you have to multiply each side by 2 cus there are the front and backside (You can draw the box with its dimensions to see the 3 types of surfaces and why I multiplied by 2):
(2×12×6) + (2×12×10) + (2×6×10) = 144 + 240 + 120
= 504ft²
9. The net of a cylinder contains two circles of radius 24yd and one long sheet to wrap around the circles with the length that is the circumference of the circle (so that it can wrap around the two circles) and a width which is the height of the cylinder (9yd).
2 Circles = 2×pi×24×24
= 1152pi
Long sheet = 9×24×2×pi
= 432pi
Now we can add all of them together:
432pi+1152pi = 1584pi
= 4970yd² (rounded to 3 s.f.)
Answer:
0.64 kilometres
Step-by-step explanation:
<u>Step 1: Find the perimeter in metres</u>
Perimeter of square = 4 x (Length)
Perimeter = 4 (160)
Perimeter = 640 metres
<u>Step 2: Convert from metre to kilometre</u>
1 km = 1000 m
x km = 640 m
<em>Cross multiply</em>
1000x = 640
x = 0.64 kilometres
Therefore, the perimeter of the square base is 0.64 kilometres.
!!
2. B 60 meters
3. C. 10yd
Refer to the attachment for complete calculation
Answer:
50% is the increase
Step-by-step explanation:
Answer:
The height of the trapezoid is 4ft
Step-by-step explanation:
First of all, to solve this problem we need to use the area formula of a trapezoid:
A = area = 20ft²
b1 = base 1
b2 = b2
h = height
b1 + b2 = 10ft
A = ½ (b1+b2) * h
we replace with the known values
20ft² = ½ (10ft) * h
20ft² = 5ft * h
20ft² / 5ft = h
4ft = h
The height of the trapezoid is 4ft
