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lesya [120]
3 years ago
11

What is the equation of a line that passes through the point (8,1) and is perpendicular to the line whose equation is y= -2/3 x

+ 5?
A) 2X+3Y= 15
B) Y= -2/3x + 11
C) Y= 3/2x+ 11
D) y= 3/2x - 11

I am thinking its B but am not sure. I don't wanna retake this so I wanna be 100%. Thanks!!
Mathematics
1 answer:
Alik [6]3 years ago
7 0

Answer:

The equation of this line would be y = 3/2x - 11, which is the answer D.

Step-by-step explanation:

In order to find this equation we must first find the slope of the original line. The original slope (the coefficient of x) is -2/3, which means the new slope will also be 3/2 because perpendicular lines have opposite and reciprocal slopes. Now, we can use this slope along with the point in point-slope form to find the equation of the line.

y - y1 = m(x - x1)

y - 1 = 3/2(x - 8)

y - 1 = 3/2x - 12

y = 3/2x - 11

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