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elena-s [515]
2 years ago
6

Determine if the following lines are parallel (never intersect), perpendicular (intersect at a 90 degree angle), intersecting (i

ntersect at just one point), or coinciding (intersect at all points)?
y = -6x − 8, -x + 6y = 12

Mathematics
1 answer:
mihalych1998 [28]2 years ago
7 0

Answer:


These lines are perpendicular.

Step-by-step explanation:

Put both equations in the slope intercept form of a line.

y = -6x - 8  This is already in the slope intercept form for a line

-x + 6y = 12  Add x to both sides of the equation

6y = x + 12  Divide through the whole equation by 6

y = 1/6x +2  

Now we compare the two slopes of -6 and 1/6.  They are negative reciprocals of each other.  That means that the line are perpendicular.

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Answer:

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Step-by-step explanation:

<u>Step 1: Define</u>

[Given] f(x) = x²

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<u>Step 2: Find</u>

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4 0
3 years ago
Factor the trinomial 10x^2 + 11x - 6
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Answer:

Step-by-step explanation:

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A line is perpendicular to y = {2/3x + 2/3}
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As this line passes through (-2,4), putting these values in this equation gives  c = 1.

Hence the answer is y = (-3x/2) + 1

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6 0
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