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elena-s [515]
2 years ago
6

Determine if the following lines are parallel (never intersect), perpendicular (intersect at a 90 degree angle), intersecting (i

ntersect at just one point), or coinciding (intersect at all points)?
y = -6x − 8, -x + 6y = 12

Mathematics
1 answer:
mihalych1998 [28]2 years ago
7 0

Answer:


These lines are perpendicular.

Step-by-step explanation:

Put both equations in the slope intercept form of a line.

y = -6x - 8  This is already in the slope intercept form for a line

-x + 6y = 12  Add x to both sides of the equation

6y = x + 12  Divide through the whole equation by 6

y = 1/6x +2  

Now we compare the two slopes of -6 and 1/6.  They are negative reciprocals of each other.  That means that the line are perpendicular.

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adoni [48]
2. 8x -28 = -140
8x -28 + 28 = -140 + 28
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8x/8 = -112/8
x = -14

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-9 + 9 + x/3 = -23 + 9
x/3 = -14
x/3/3 = -14/3
x = -14/3

4. x/-1.5 - 3.5 = -13.5
x/-1.5 - 3.5 + 3.5 = -13.5 + 3.5
x/1.5 = -10
x/-1.5/-1.5= -10/-1.5
x = 20/3

5.-6(x + 3) = -36
-6x - 18 = -36
-6x - 18 + 18 = -36 + 18
-6x = -18
-6x/-6 = -18/-6
x = 3

6. k + 3.7/9.8 = -0.22
k + 3.7/9.8/9.8 = -0.22/9.8
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k + 3.7 - 3.7 = -2.156 - 3.7
k = -5.856

7. 12(x - 6) = -108
12x - 72 = -108
12x - 72 + 72 = -108 + 72
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8. -21.83x - -19.9 = -23.83
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9. -10x - 68 + x = 40
-9x - 68 = 40
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-5x - 77 + 77 = 23 + 77
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x = -7










5 0
3 years ago
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Using Pythagorean, a^2 + b^2 = c^2
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