All categories

3 years ago

Find an equation of the plane that passes through the origin and its perpendicular to the vector [1,-2,5]

Mathematics

1 answer:

Volgvan3 years ago

8 0

Answer:

x - 2y + 5z = 0

Step-by-step explanation:

The standard equation is of the form, Ax + By + Cz = 0

The equation of the plane that passes through the origin(0, 0, 0) and is perpendicular to [1, -2, 5] is

A = 1, B = -2, C = 5

x = y = z = 0 (at origin)

A(x-0) + B(y-0) + C(z-0) = 0

(x - 0) -2(y-0) + 5(z-0) = 0

x - 2y + 5z = 0

You might be interested in

Jon has $5,000 to invest in a savings account that has interest compounded annually. If he want his money to double in eight yea

Nataly_w [17]

$5000 × 1.1%=$55

$55 × 12 mos. in a year= $660 yearly on this percent

calculate
$660 × 8 years from now =$5280

so the answer would be 1.1% I assume

6 0

3 years ago

On a coordinate plane, a line is drawn from point A to point B. Point A is at (2, negative 3) and point B is at (negative 4, 9).

zimovet [89]

Answer: (0,1)

Step-by-step explanation:

If $(x_1, y_1)$ and $(x_2, y_2)$ are two point son a coordinate plane and (x,y) dividing it in a ratio of m: n.

Then , the coordinates of (x,y) is given by :-

$x=\dfrac{nx_1+mx_2}{m+n}$

$y=\dfrac{ny_1+my_2}{m+n}$

Given : On a coordinate plane, a line is drawn from point A to point B. Point A is at (2, - 3) and point B is at (- 4, 9).

Then , the x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2 :

$x=\dfrac{2(2)+1(-4)}{1+2}=0$

$y=\dfrac{2(-3)+1(9)}{1+2=1}$

Hence, the x- and y- coordinates of point E = (0,1)

3 0

3 years ago

Read 2 more answers

Line AB goes through the points A (0, –4) and B (6, 2). Which equation represents line AB?

insens350 [35]

Answer:

Option C) y + 4 = x

Step-by-step explanation:

We are given the following information in the question:

Line AB goes through the points A (0, –4) and B (6, 2).

We can use the two-point form of equation of straight line.

The equation of line is given by:

$(y-y_1) = \displaystyle\frac{y_2-y_2}{x_2-x_1}(x-x_1)$

where, $(x_1,y_1), (x_2.y_2)$ is the point through which the line passes.

The equation of line is:

$(y+4) = \displaystyle\frac{2+4}{6-0}(x-0)\\\\(y+4)= x\\y = x-4$

Thus, the equation of line AB is given by Option C) y + 4 = x

7 0

3 years ago

Read 2 more answers

Please<br> Help !!!!!!!!!!!

slava [35]

Answer:

Painting USA is cheaper. They cost $700 dollars. The other place costs $1,000 dollars

7 0

3 years ago

Describe how to solve an exponential equation with unlike bases.

kari74 [83]

Answer:

Mark me as brainlist

Step-by-step explanation:

Use logarithms to solve exponential equations whose terms cannot be rewritten with the same base

Solve exponential equations of the form

for t

Recognize when there may be extraneous solutions or no solutions for exponential equations

4 0

3 years ago

Read 2 more answers