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katrin [286]
3 years ago
6

How much would $500 invested at 7% interest compounded annually be worth after 4 years? Round your answer to the nearest cent. A

. $640.00 B. $655.40 C. $535.93 D. $661.56
Mathematics
1 answer:
Flura [38]3 years ago
5 0
The answer is B.  Here's the formula: Amount = Principle(1 + rate)^time. Your variables are P= 500, r = .07, and t= 4. Set it up like this: A = 500(1+.07)^4. Add inside the parenthesis first and then raise that number to the 4th power to get 500(1.31079601). Do that multiplication to get $655.40
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One-third of a number decreased by six equals eight. What is the number?<br> 6
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Answer:

42

Step-by-step explanation:

1/3 x 42 = 14

14 - 6 = 8

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12=15(z-1/5) <br><br> Solve for z.
Inga [223]
The answer would be Z = 1
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A 21-pound turkey was cooked for a small banquet. The caterer figures he will discard (throw away) 5 pounds of bones and that ea
qaws [65]

Answer:

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Step-by-step explanation:

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3 years ago
A home gardener estimates that 24 apple trees will have an average yield of 104 apples per tree. But because of the size of the
d1i1m1o1n [39]

Answer:

The farmer should plant 14 additional trees, for maximum yield.

Step-by-step explanation:

Given

Trees = 24

Yield = 104

x \to additional\ trees

So, we have:

Trees = 24 + x

Yield = 104 - 2x

Required

The additional trees to be planted for maximum yield

The function is:

f(x) = Trees * Yield

f(x) = (24 + x) * (104 - 2x)

Open bracket

f(x) = 24 * 104 + 104x - 24 * 2x - x * 2x

f(x) = 2796 + 104x - 48x - 2x^2

f(x) = 2796 + 56x - 2x^2

Rewrite as:

f(x) = - 2x^2 + 56x + 2796

Differentiate

f'(x) = -4x + 56

Equate f'(x) = -4x + 56 to 0 and solve for x to get the maximum of x

-4x + 56 = 0

-4x =- 56

Divide by -4

x =14

The farmer should plant 14 additional trees, for maximum yield.

5 0
3 years ago
In a recent international sport competition, the top 3 countries— Country A, Country B, and Country C— won a total of 134 medals
vlada-n [284]

Answer:

Country A = 85, Country B = 29, Country C = 20

Step-by-step explanation:

A+B+C=134 ----- eq(1)

B=C+9 ------------ eq(2)

A=36+B+C ------ eq(3)

By substituting eq(2) in eq(3), we get:

A=36+C+9+C

A=2C+45 ------- eq(4)

Now substituting eq(2) & eq(4) in eq(1), we get

2C+45+C+9+C=134

4C+54=134

4C=134-54

4C=80

C=20

Now putting the value of C in eq(2),

B=20+9

B=29

Substituting the value of B & C in eq(1), we get:

A+29+20=134

A+49=134

A=134-49

A=85

6 0
3 years ago
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