Answer:

Step-by-step explanation:
Here,
f(x) = y

or , swapping x with y

now to solve for y we get

now we put f inverse x instead of y

I am done.
Step-by-step explanation:
please check your question once and chose correct answer which one is helpful to you
Answer:
Z' = (-5,3)
Step-by-step explanation:
Move two to the (<- left) from -3,5 to get -5, 5
move two down to get -5,3
I'm assuming all of (x^2+9) is in the denominator. If that assumption is correct, then,
One possible answer is 
Another possible answer is 
There are many ways to do this. The idea is that when we have f( g(x) ), we basically replace every x in f(x) with g(x)
So in the first example above, we would have

In that third step, g(x) was replaced with x^2+9 since g(x) = x^2+9.
Similar steps will happen with the second example as well (when g(x) = x^2)
Answer:
7
Step-by-step explanation: