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Dima020 [189]
3 years ago
9

The central angle of a half circle is 180 degrees. The central angle of a quarter circle is 90 degrees. How many degrees is the

central angle of an eighth of a circle?

Mathematics
1 answer:
velikii [3]3 years ago
7 0
Total circle = 360°
1/2 of circle = 1/2 x 360 = 180°
1/4 of the circle = 1/4 x 360 = 90°

Similarly,
1/8 of the circle = 1/8 x 360 = 45°
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Use the diagram to complete the table by matching the Theorem with the angle relationship.
serious [3.7K]

Answer:

The Table with Correct reasons are as follows.

Step-by-step explanation:

The Table with Correct reasons are as follows

       Answer                                                  Angle Relationship

c. Corresponding Angles                       ∠ 1 ≅ ∠ 5

d. Same Side Interior                             ∠ 4 + ∠ 5 = 180

a. Alternate Exterior Angles                    ∠ 3 ≅ ∠ 6

b. Alternate Interior Angles                    ∠ 4 ≅ ∠ 5

c. Corresponding Angles                       ∠ 2 ≅ ∠ 6

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3 years ago
HURRY FROM ODDESYWARE
antoniya [11.8K]
It should be the last one but sorry if i’m wrong
6 0
3 years ago
Calculate the perimeter of the quadrilateral. Trapezoid
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I need to know the sides of the trapezoid in order to find the perimeter
8 0
3 years ago
What would Y be equal to in the problem 0.5x + 0.6y = 5.4
Alla [95]

Answer:

y = -\frac{5}{6}x + 9

Step-by-step explanation:

0.5x + 0.6y = 5.4

0.6y = -0.5x + 5.4

Multiply 10 on all sides.

6y = -5x + 54

Divide 6 on all sides.

y = -\frac{5}{6}x + 9

7 0
2 years ago
During which time period does Landon's elevation change the fastest? Explain how you know?
bogdanovich [222]
<h3>1. How many inches per minute does London's elevation change between 4 minutes and 8 minutes. </h3>

The question actually asks for the slope of the line that stands for the points (4,3) \ and \ (8,6) why? because the questions tells us that London's elevation changes between 4 minutes and 8 minutes here. Hence, to find the slope of this line we have to use the following formula:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6)

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6) \\ \\ So: \\ \\ m=\frac{6-3}{8-4}=0.75in/min

<em>So London's elevation changes 0.75 inches per minute</em>

<em></em>

<h3>2. During which time period does London's elevation change the fastest?</h3>

The greater the absolute value of the slope of the line the faster London's elevation changes. Since this is a Piecewise function, we must analyze each period.

  • FIRST:

→ Between 0 minutes and 4 minutes the function is constant, so there is no any change here.

→ Between 10 minutes and 14 minutes the function is constant, so there is no any change here.

→ Between 18 minutes and 22 minutes the function is constant, so there is no any change here.

So the solution is not in these parts of the function.

  • SECOND:

→ Between 4 minutes and 10 minutes the function has a positive slope, so there is change here.

In the previous item we calculated the slope between 4 and 8 minutes that is the same slope between 4 and 8 minutes and equals 0.75.

→ Between 14 minutes and 18 minutes the function has a positive slope, so there is change here.

Let's take two points here, say, (16,5) \ and \ (18,3)

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(16,5) \\ P(x_{2},y_{2})=P(18,3) \\ \\ So: \\ \\ m=\frac{3-5}{18-16}=-1 in/min

As you can see, the absolute value here is 1 that is greater than 0.75.

<em>In conclusion, London's elevation changes the fastest between 14 and 18 minutes</em>

7 0
3 years ago
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