Answer:
B the answer is no solution
Answer:
1) 47/54 probability that the selected person is someone who was not ticketed, given it is a woman.
2) 8/41 probability that the selected person is someone who was not ticketed, given it is a man.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
1. What is the probability that the selected person is someone who was not ticketed, given it is a woman?
7 + 47 = 54 total woman
47 were not ticketed. So
47/54 probability that the selected person is someone who was not ticketed, given it is a woman.
2. What is the probability that the selected person is someone who was not ticketed, given it is a man?
33 + 8 = 41 men.
8 were not ticketed. So
8/41 probability that the selected person is someone who was not ticketed, given it is a man.
<span>2.25 + 2.25x + 1 - 0.75x + 2x = 3.5x + 3.25</span>
Answer:
yes verified
Step-by-step explanation:
2x-y+1=0
substitute
2(2)-5+1=(0?)
4-5+1=0
yes
A) 1st Row = 31 seats
2nd row = 37 seats
3rd row = 37+6 = 43 seats
4th row = 43+6 = 49 seats
5th row = 49+6 = 55 seats
B) The formula for finding the number of seats in any row number is:
Number of seats in nth row = 31 + (n-1) *6
C) To find the row with 103 seats, set the equation in B to equal 103 and solve for n:
103 = 31 + (n-1)*6
Subtract 31 from each side:
72 = (n-1)*6
Divide both sides by 6:
12 = n-1
add 1 to each side:
n = 13
The 13th row has 103 seats.