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ziro4ka [17]
3 years ago
5

Brent has a collection of 84 Bobble Head trophies he needs to box up for the move to his new home. He can fit 7 trophies into on

e box. How many boxes will Brent need?
*Please Show Work*
Mathematics
1 answer:
Alina [70]3 years ago
7 0

\displaystyle \frac{84\,\text{trophies}}{\left(\frac{7\,\text{trophies}}{\text{box}}\right)}=\frac{84}{7}\,\text{box}\\\\=12\,\text{box}

Brent will need 12 boxes.

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FIRST.

64 square inches matches to a cross section parallel to the base of a right rectangle prism that is 3 inches long, 7 inches wide, and 11 inches tall

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SECOND.

64 square inches matches to a cross section parallel to the base of a cube whose edges are 8 inches long.

This is shown in the second figure below. A cube is a prism whose sides all have the same length and in this case is 8 inches. We name cross section is to the slice that cuts through a solid. If the cross section is parallel to the base of a cube, then it forms a square with length . Therefore, the area of this shape can be found as the area of a square, which is: 64 in squared.

Third.

7 square inches matches to a cross section passing through the diagonal of opposite faces of a cube with edges that are 7 inches long and a diagonal that is approximately 10 inches

This is shown in the third figure below. As you can see, the cross section passes through the diagonals of the base and the top of the cube that are two opposite faces. This form a rectangle having sides  where:

So: 70 in squared

FOURTH.

300 square inches matches to a cross section perpendicular to the base and passing through the diagonals of the base and opposite face of a right rectangular prism that is 24 inches wide, 7 inches long, and 12 inches tall and measures 25 inches along the diagonal of the base.

This is shown in the fourth figure below. The cross section passes through the diagonals of the base and the top of the right rectangular prism. They are opposite to each other, so the shape of the cross section is a rectangle whose sides are  where:

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Step-by-step explanation:

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3 years ago
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Draw a set of coordinate axes.  Draw light horizontal lines through y=3 and y=-3.  These are the max and min. values of this sine function.

Plot the phase shift on your x-axis.

Your sine function will begin at (phase shift value, 0) and continue for one period.  Add the period to the phase shift value.  Draw a sine curve beginning and ending at these two x-values.

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3 0
3 years ago
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nevsk [136]

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