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Rudik [331]
3 years ago
7

PLEASE HELP What is (-1,2) and (1,-4) in slope-intercept form?

Mathematics
1 answer:
AlexFokin [52]3 years ago
8 0

I believe the answer would be y = –3x – 1.

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Ms. Campbell is hosting a toy drive
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Answer:

whos your teacher ? i had a teacher that named ms.campbell

Step-by-step explanation:

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2 years ago
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using whole numbers, fractions, and decimals, write at least eight addition equations that have the sum of 10
LuckyWell [14K]
<span>Using whole numbers, fractions, and decimals, these are the eight addition equations that have the sum of 10
</span>1. 5+5=10
2. 1 1/2 + 8 1/2 =10
3. 2.9+7.1=10
4. 6 1/3 + 3 2/3 =10
5. 4 3/5 + 5 2/5=10
6. 9.01+.99=10
7. 3.72+6.28 = 10
8.  8 8/9+ 1 1/9=10
7 0
3 years ago
Question
ANTONII [103]

The approximate area of the park on the grid is: E. about 40 km² to 50 km².

<h3>How to Find the Approximate Area on a Coordinate Grid?</h3>

The number of square on a coordinate grid that is covered determines the area covered. We can make an estimate by counting how many of this square on the coordinate grid that is covered, then find out the area depending on how much square area each grid represents.

In the coordinate plane given, which shows a park, we are told that each of the square on the grid equals 1 k = square kilometer.

The number of each of these squares we can find that is covered by the park on the grid is: 48 squares.

Therefore, the area of 48 squares on the grid = 48 × 1 = 48 km². Since not all squares are fully covered by the park, we can state that the approximate area of the park on the grid is: E. about 40 km² to 50 km².

Learn more about the approximate area on a grid on:

brainly.com/question/368985

#SPJ1

7 0
1 year ago
A genetic experiment involving peas yielded one sample of offspring consisting of 420 green peas and 174 yellow peas. Use a 0.01
slavikrds [6]

Answer:

a) z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649  

b) For this case we need to find a critical value that accumulates \alpha/2 of the area on each tail, we know that \alpha=0.01, so then \alpha/2 =0.005, using the normal standard table or excel we see that:

z_{crit}= \pm 2.58

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

Step-by-step explanation:

Data given and notation

n=420+174=594 represent the random sample taken

X=174 represent the number of yellow peas

\hat p=\frac{174}{594}=0.293 estimated proportion of yellow peas

p_o=0.23 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of yellow peas is 0.23:  

Null hypothesis:p=0.23  

Alternative hypothesis:p \neq 0.23  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>3.649)=0.00026  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

b) Critical value

For this case we need to find a critical value that accumulates \alpha/2 of the area on each tail, we know that \alpha=0.01, so then \alpha/2 =0.005, using the normal standard table or excel we see that:

z_{crit}= \pm 2.58

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

5 0
3 years ago
4x-2y=8(x-3) <br><br> x= ?<br> y= ?
Rainbow [258]

x = -6 y/2

y = -2x + 12

hope that helped

6 0
2 years ago
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