Answer:
Hey! The answer you're looking for is D. Uniform Resource Locator.
Answer:
do you still need the answer? or am i to lateeee
Explanation:
Answer:
Option 1: May crash at runtime because it can input more elements than the array can hold
Explanation:
Given the code as follows:
- int[] a = {1, 3, 7, 0, 0, 0};
- int size = 3, capacity = 6;
- int value = cin.nextInt();
- while (value > 0)
- {
- a[size] = value;
- size++;
- value = cin.nextInt();
- }
From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.
However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist. This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.
Answer:
true
Explanation:
Based on the information provided within the question it can be said that this statement is completely true. Programming code is built as a series of steps that are followed in a linear way. So much so that one action needs to be completed before another action can begin. There are also conditions such as, if step 1 is true then execute step 2, these are all sequences that must be understood by the individual writing the code.
Answer:
answer is 8! / (4! * 4!). Which gives a value of 70.
Explanation:
we have 8 places, we’re going to pick 4 places to put the zeros, it is 8! / (4! x 4!)
