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Montano1993 [528]
3 years ago
8

The population of a county is growing at a rate of 9% per year, compounded continuously. How many years will it take for the pop

ulation to quadruple according to the exponential growth function?
Mathematics
1 answer:
torisob [31]3 years ago
8 0

Answer:

t=15.4\ years

Step-by-step explanation:

The  exponential growth function compounded continuously is equal to

A=P(e)^{rt}  

where  

A is the final population  

P is the initial population  

r is the rate of growth in decimal  

t is Number of years

e is the mathematical constant number

we have  

A=4x\\P=x\\ r=9\%=9/100=0.09  

substitute in the function above

4x=x(e)^{0.09t}    

simplify

4=(e)^{0.09t}

Take natural log of both sides

ln(4)=ln[(e)^{0.09t}]

ln(4)=0.09t(ln(e))

ln(e)=1

ln(4)=0.09t

t=ln(4)/0.09

t=15.4\ years

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3 0
3 years ago
In studies for a​ medication, 3 percent of patients gained weight as a side effect. Suppose 643 patients are randomly selected.
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Part a)

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This means

p = 0.03

q = 1 - 0.03 = 0.97

The mean is

\mu  = np

\mu = 643 \times 0.03 = 19.29

The standard deviation is

\sigma =  \sqrt{npq}

\sigma =  \sqrt{643 \times 0.03 \times 0.97}

\sigma =4.33

We want to find the probability that exactly 24 patients will gain weight as side effect.

P(X=24)

We apply the Continuity Correction Factor(CCF)

P(24-0.5<X<24+0.5)=P(23.5<X<24.5)

We convert to z-scores.

P(23.5 \: < \: X \: < \: 24.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \:  \frac{24.5 - 19.29}{4.33} ) \\  = P( 0.97\: < \: z \: < \:  1.20) \\  = 0.051

Part b) We want to find the probability that 24 or fewer patients will gain weight as a side effect.

P(X≤24)

We apply the continuity correction factor to get;

P(X<24+0.5)=P(X<24.5)

We convert to z-scores to get:

P(X \: < \: 24.5) = P(z \: < \:  \frac{24.5 - 19.29}{4.33} )  \\ =   P(z \: < \: 1.20)  \\  = 0.8849

Part c)

We want to find the probability that

11 or more patients will gain weight as a side effect.

P(X≥11)

Apply correction factor to get:

P(X>11-0.5)=P(X>10.5)

We convert to z-scores:

P(X \: > \: 10.5) = P(z \: > \:  \frac{10.5 - 19.29}{4.33} )  \\ = P(z \: > \:  - 2.03)

= 0.9788

Part d)

We want to find the probability that:

between 24 and 28, inclusive, will gain weight as a side effect.

P(24≤X≤28)=

P(23.5≤X≤28.5)

Convert to z-scores:

P(23.5  \:  <  \: X \:  <  \: 28.5) = P( \frac{23.5 - 19.29}{4.33}   \:  <  \: z \:  <  \:  \frac{28.5 - 19.29}{4.33} ) \\  = P( 0.97\:  <  \: z \:  <  \: 2.13) \\  = 0.1494

3 0
3 years ago
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