Answer![\sqrt[4]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B6%7D)
![\sqrt[4]{b^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bb%5E3%7D)
![\sqrt[4]{c}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bc%7D)
Step-by-step explanation:
Step-by-step explanation:
the last one
x^2+2x+1 R(-5)
Vcylinder-Vsphere=water
Vcylinder=hpir^2
Vsphere=(4/3)pir^3
given
cylinderradius=30 and h=100
Vcylinder=100pi30^2=100pi900=90000pi
let's leave it in terms of pi for more exactness
sphereradius=12
Vsphere=(4/3)pi12^3=2304pi
cylinder-sphere=90000pi-2304pi=87696pi
using pi=3.14
water=275365.44 cubic cm
last option is corrrect
Answer:
10.6
Step-by-step explanation:
1. First, we need to find which digits √(113) is between, and that would be 10 and 11.
2. Okay, so √(113) is between 10 and 11, meaning 113 is between 100 and 121.
3. Since 113 is a little over half between 100 and 121, let's multiply 10.6 by 10.6 to see how close we are to 113:
4. 112.36 is pretty close to 113, therefore, the dot on the number-line should be placed at 10.6.
Answer:$8.60
I put the work into the picture. Hope this helps!