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gladu [14]
3 years ago
7

is it better to buy 3 gifts and get one free or use a coupon for 20% off of three. which is cheaper i’m too lazy to do it :~|

Mathematics
2 answers:
Svetach [21]3 years ago
8 0

Answer:

coupon

Step-by-step explanation:

FrozenT [24]3 years ago
5 0

Answer:

Coupon

Step-by-step explanation:

C O U P O N

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A catering company loses $110 as a result of a delay.
tatyana61 [14]

Answer:What you have to do first is you have 5 owners correct? Well you take anything they're sharing in this case it's delay/debt, so you divide $110 by 5 and you should get $22. This means that each owner would have to pay $22 for the delay.

ANS -22

Brainly please

4 0
3 years ago
Suppose that the relation G is defined as follows.
Serga [27]

G:{3,4,6}->{0,9}

The pairs represent the input (first number in each pair) and the result (second nu.ber in each pair) for the relation G. for example G(3)=9.

The domain is the set of values that the relation can act upon. The range is the set of the values the results can take

6 0
3 years ago
Are the equations 3x=−9 and 4x=−12 equivalent? Explain.<br> yes they are
My name is Ann [436]

Step-by-step explanation:

Yes they are equivalent. You get -3 when you try solving the actual equation.

5 0
3 years ago
Nine eighteenths plus one third
lisov135 [29]

Answer:

5/6

Step-by-step explanation:

Step 1: Rewrite 9/18

9/18 = 1/2

Step 2: Rewrite problem

1/2 + 1/3

Step 3: Find GCD (Greatest common denominator)

6

Step 4: Rewrite fractions

3/6 + 2/6

Step 5: Add

5/6

6 0
3 years ago
Read 2 more answers
Consider the following functions. f1(x) = x, f2(x) = x2, f3(x) = 2x − 4x2 g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, a
bekas [8.4K]

9514 1404 393

Answer:

  • (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
  • NOT linearly independent

Step-by-step explanation:

We want ...

  c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0

Substituting for the fn function values, we have ...

  c1·x +c2·x² +c3·(2x -4x²) ≡ 0

This resolves to two equations:

  x(c1 +2c3) = 0

  x²(c2 -4c3) = 0

These have an infinite set of solutions:

  c1 = -2c3

  c2 = 4c3

Then for any parameter t, including the "trivial" t=0, ...

  (c1, c2, c3) = (-2t, 4t, t)

__

f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)

7 0
2 years ago
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