Six less than "b"
i think this would be the answer
good luck!!
<span>Exactly 33/532, or about 6.2%
This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball.
There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red.
Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133.
So the combined probability of both of the 1st 2 gumballs being red is
1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
YOU DON"T HAVE TO YELL
512 PER STUDENT
BASICALLY,
CUBES NEEDED=CUBES PER STUDENT TIMES NUMBER OF STUDENTS
NUMBER OF STUDENTS=28+25=53
CUBES PER STUDENT=512
CUBES NEEDED=512 TIMES 53 EQUALS 27136 CUBES
SHE NEEDS 27136 CUBES FOR ALL HER STUDENTS
754,863 rounded to the nearest ten thousands is 750,000
