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tiny-mole [99]
3 years ago
15

Which of the following pairs of elements are likely to form an ionic compound? Check all that apply. Check all that apply. lithi

um and chlorine potassium and oxygen sodium and neon cesium and magnesium oxygen and bromine nitrogen and fluorine
Business
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

lithium and chlorine

potassium and oxygen

Explanation:

Ionic compound are chemical compound held by electrostatic forces known as ionic bonding. Ionic compound, their is transfer of electron. One atom of element lose electron while the other atom gain electron. The ions involve in bonding are known as cations and anions.

The cations loses electron to become positively charged while the anion receive electron to become negatively charged. An ionic compound possess an anion and a cations. The electronegativity difference between the atom that go into bonding is widely different.  

The best option is the bonding between lithium (cations) and chlorine(anions) and potassium(cations) and oxygen(anions).

The bonding is usually between a metal and a non metal.

Li + and  Cl- → LiCl

K+ and O2- → K2O

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The quantity demanded x for a product is inversely proportional to the cube of the price p for p > 1. When the price is $10 p
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Answer:

$6.00

Explanation:

Given data

quantity demanded ( x )  ∝ 1 / p^3       for p > 1

when p = $10/unit , x = 64

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<u>Determine the price that will yield a maximum profit </u>

x = k/p^3 ----- ( 1 ).  when x = 64 , p = $10 , k = constant

64 = k/10^3

k = 64 * ( 10^3 )

  = 64000

back to equation 1

x = 64000 / p^3

∴ p = 40 / ∛x

next calculate the value of revenue generated

Revenue(Rx) = P(price ) * x ( quantity )

               = 40 / ∛x * x   =  40 x^2/3

next calculate Total cost of product

C(x) = 140 + 4x

Maximum Profit  generated = R(x) - C(x) = 0

                                              = 40x^2/3 - 140 + 4x  = 0

                                              =  40(2/3) x^(2/3 -1) - 0 - 4 = 0

                                            ∴ ∛x = 20/3    ∴     x = (20/3 ) ^3 = 296

profit is maximum at x(quantity demanded ) = 296 units

hence the price that will yield a maximum profit

P = 40 / ∛x

  = ( 40 / (20/3) )  = $6

                                             

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Answer:

b. $20,000

Explanation:

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