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3 years ago

What should I do here?

Mathematics

1 answer:

Otrada [13]3 years ago

8 0

Divide the amount from the months , then add the percentage

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Jared painted 5/12 and 4/12 blue.what part of the mug is not red or blue?

Reika [66]

3/12 of the mug is not blue or red

7 0

3 years ago

Find the inverse or opposite of (2n-8)

asambeis [7]

the additive inverse of -8 is 8

to find the additive inverse you just have to change the sign of the number

5 0

3 years ago

Please help, this is due today:

Marina86 [1]

Answer:

x = 17

Step-by-step explanation:

∠ DCE = ∠ ACE ( vertically opposite angles )

The sum of the 3 angles in a triangle = 180° , then

∠ DCE = 180° - (100 +x) = 180 - 100 - x = 80 - x

∠ ACE = 180 - (49 + 4x) = 180 - 49 - 4x = 131 - 4x

Equating the 2 angles

80 - x = 131 - 4x ( add 4x to both sides )

80 + 3x = 131 ( subtract 80 from both sides )

3x = 51 ( divide both sides by 3 )

x = 17

8 0

2 years ago

For his birthday, Mr. Robin and four of his friends went to a Math museum to learn about new intergalactic math. They each got a

Helen [10]

Answer: $10

Step-by-step explanation:

Given

Robin and his four friends bought tickets for $\$12$ each

If each one of them bought a calculator then the total spendings are $\$110$

Suppose the cost of each calculator is $\$\ x$

Cost per person is given by $x+\$12$

For the group, it is $5(x+12)$

Equate this to total spendings

$\Rightarrow 5(x+12)=110\\\Rightarrow x+12=22\\\Rightarrow x=\$\ 10$

thus, the cost of each calculator is $\$ 10$

4 0

3 years ago

Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2

Basile [38]

Answer:

$f(x) = x^3 - 2x^2 -3x + 6$

Step-by-step explanation:

According to the Factor Theorem, if (x - k) is a factor of a polynomial P(x), then P(k) must equal zero.

We are given that a polynomial function has the zeros 2, √3, and -√3. So, we can let k = 2, √3, -√3.

So, according to the Factor Theorem, P(2), P(√3) and P(-√3) must equal 0.

Testing each choice, we can see that only A is true:

$\displaystyle f(x) = x^3 - 2x^2 - 3x + 6$

Testing all three values yields that:

$\displaystyle \begin{aligned} f(2) &= (2)^3 - 2(2)^2 -3(2) + 6 \\ &= (8) - (8) -(6) + (6) \\ &= 0\stackrel{\checkmark}{=}0 \\ \displaystyle f(\sqrt{3}) &= (\sqrt{3})^3 - 2(\sqrt{3})^2 - 3(\sqrt{3}) + 6 \\ &=(3\sqrt{3}) -(6)-(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \\ f(-\sqrt{3}) &= (-\sqrt{3})^3 - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 \\ &=(-3\sqrt{3}) -(6)+(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \end{aligned}$

Hence, our answer is A.

3 0

3 years ago