I’ve attached my work...
Hope it helps! Have a nice day :)
The problem on the left is going to be 1 tens and 8 ones, so 18.
The problem on the right is going to be 2 tens and 9 ones, so 29.
The letter 'C' has 2 lines of symmerty
the upper-case 'D' has 2 lines of symmetry
the uper -case 'E' has 2 lines of symmetry
the upper case 'H' has 2 lines of symmetry
the upper case 'I' has 2 lines of symmetry
the small case 'L' has 2 lines of symmmetry
the letter 'O' has infinite lines of symetry
the letter 'x' has 4 lines of symmetry
1st picture
The average speed for his journey from York to Blackpool is 61.4 KM/H
We have the base measurement for the triangles composing the sides. We need their altitude.
Imagine a right triangle with these sides:
(1) from the apex of the pyramid to the point on the base directly underneath it (471 ft);
(2) from the middle of base edge to the point underneath the apex (half of 708 ft = 354 ft);
(3) the hypotenuse, the altitude of a triangular side.
Using the Pythagorean Theorem, we find the hypotenuse to be
√(471^2 + 354^2) = about 589.2 feet
Now we add up the four triangles' areas. Each is base * altitude / 2, so:
4 x 708 x 589.2 / 2
= 2 x 708 x 589.2
= 834,307.2 square feet, the lateral area.
