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Oksanka [162]
3 years ago
10

Dotty is 51 years old and Esmerelda is 23. How many years ago was Dotty 3 times Esmerelda's age?

Mathematics
1 answer:
kari74 [83]3 years ago
3 0

Answer:

9 years ago.

Step-by-step explanation:

Dotty is 51 years old and Esmerelda is 23 now.

Now, x years ago the age of Dotty was (51 - x) years and the age of Esmerelda was (23 - x) years.

Assume that x years ago Dotty was 3 times Esmerelda's age.

So, we can write the equation as

3(23 - x) = 51 - x

⇒ 69 - 3x = 51 - x

⇒ 69 - 51 = 3x - x

⇒ 18 = 2x

⇒ x = 9 years.

Therefore, 9 years ago Dotty was 3 times Esmerelda's age. (Answer)

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Step-by-step explanation:

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3 times a number is 54 less than the square of that number. Find the negative solution.
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x=-6

Step-by-step explanation:

Let x be the number

3x = x^2 -54

Subtract 3x

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Using the zero product property

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3. (05.06 MC)
AveGali [126]

Answer:

Step-by-step explanation:

y > 3x + 10

y < -3x - 1

<h3> Part A:</h3>

You'd graph the given systems of linear inequalities the same way as you graph the linear equations.  

To graph y > 3x + 10, plot the y-intercept, (0, 10), then use the slope, m = 3 (rise 3, run 1), to plot other points on the graph.  Use a dashed line (because of the ">" symbol).  

Follow the same steps for the other linear inequality. Plot the y-intercept, (0, -1), then use the slope, m = -3 (down 3, run 1) to plot other points. Use a dashed line (because of the "<" symbol).  

Pick a test point on either side of the boundary line and plug it into the original problem.  This will help determine which side of the boundary line is the solution.  Plug in a test point that is not on the boundary line.

Use the point of origin, (0, 0) as the test point. Plug in these values into the given systems of linear inequalities to see whether it will provide a true statement.  

y > 3x + 10

0 > 3(0) + 10

0 > 0 + 10

0 > 10 (False statement).  

y < -3x - 1

0 < -3(0) - 1

0 < 0 - 1

0 < -1 (false statement).  

Since the point of origin provided a false statement to the given systems of linear inequalities, you must shade the half-plane region where it doesn't contain the test point.  

<h3>Part B: </h3>

You'll do the same process as what I've done for the test point. Plug in the values of (8, 10) into the given systems of linear inequalities. If it provides a false statement, then it means that it is not a solution to the system.  

y > 3x + 10

10 > 3(8) + 10

10 > 24 + 10

10 > 34 (False statement).  

y < -3x - 1  

10 < -3(8) - 1

10 < -24 - 1

10 < -25 (false statement).  

Therefore, (8, 10) is not a solution to the system.    

8 0
2 years ago
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