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AysviL [449]
3 years ago
14

6. Two weather tracking stations are on the equator 159 miles apart. A weather balloon is located on a bearing of N 33°E from th

e western station and on a bearing of N 14°E from the eastern station. How far
is the balloon from the western station


Triangles 38deg West - 14deg East
Mathematics
1 answer:
alexdok [17]3 years ago
8 0

Answer:

646.39

there u go.

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One less than twice a number is greater than 7 and less than 13. Write a compound inequality to represent this and solve to find
ExtremeBDS [4]
Write the equation as such and narrow down x value being 4

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4 years ago
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20 points!!!
vitfil [10]

Step-by-step explanation:

(12x - 19y) (12x + 19y) = 144x^2-361y^2

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3 years ago
Find the midpoint of the segment with the following endpoints.<br> (7, -2) (1, -10)
dem82 [27]

Answer:

<h2>(4, -6)</h2>

Step-by-step explanation:

The formula of a midpoint of the segment AB:

M_{AB}\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)

We have A(7, -2) and B(1, -10). Substitute:

M_{AB}\left(\dfrac{7+1}{2};\ \dfrac{-2+(-10)}{2}\right)\\\\M_{AB}\left(\dfrac{8}{2};\ \dfrac{-12}{2}\right)\\\\M_{AB}(4;\ -6)

8 0
3 years ago
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A wholesaler requires a minimum of 4 items in each order from its retail customers. The manager of one retail store is consideri
Leto [7]

Answer:

The 1st graph will be perfectly matching the conditions.

Step-by-step explanation:

A wholesaler requires a minimum of 4 items in each order from its retail customers.

The manager of one retail store is considering ordering a certain number of sofas, x and a certain number of pillows that come in pairs, y.

Therefore, for y = 0, x ≥ 4 and for x = 0, y ≥ 2 to make the order of 4 items or more.  

Therefore, the equation for the order to be of 4 items will be  

x + 2y = 4.

So, the 1st graph will be perfectly matching the conditions. (Answer)

3 0
3 years ago
N=4; 2i and 3i are zeros <br> f(-1)=50
Nonamiya [84]

Solution:- \text{Let f(x) be any nth degree polynomial with n=4}\\

\text{Given that 2i and 3i are the zeroes of f(x)}

\text{so (x-2i) and (x-3i) are factors of f(x)}

\text{Since 2i is a zero of f(x) then its conjugate -2i is also a zero of f(x)}

\Rightarrow(x+2i) \text{is a factor}\\\text{Similarly, conjugate of 3i is -3i is also a zero of f(x) }\\\Rightarrow(x+3i)\text{is a factor}\\\text{So , }\\f(x)=k(x-2i)(x+2i)(x-3i)(x+3i)\\=k(x^2-(2i)^2)(x^2-(3i)^2)\\=k(x^2-4i^2)(x^2-9i^2)\\=k(x^2+4)(x^2+9)\\=k(x^4+13x^2+36)\\\text{As given}\\f(-1)=50\\\Rightarrow k((-1)^4+13(-1)^2+36)=50\\\Rightarrow k(1+13+36)=50\\\Rightarrow k(50)=50\\\Rightarrow k=1\\\text{So by substituting k=1 in f(x) we get ,}\\f(x)=(x^4+13x^2+36)

6 0
3 years ago
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