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AysviL [449]
3 years ago
14

6. Two weather tracking stations are on the equator 159 miles apart. A weather balloon is located on a bearing of N 33°E from th

e western station and on a bearing of N 14°E from the eastern station. How far
is the balloon from the western station


Triangles 38deg West - 14deg East
Mathematics
1 answer:
alexdok [17]3 years ago
8 0

Answer:

646.39

there u go.

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Write each decimal or fraction as a percent.<br><br>0.03<br>0.18<br>23/25<br><br>​
ZanzabumX [31]

Answer:

0.03 = 3%

0.18 = 18%

23/25 = 92%

Step-by-step explanation:

4 0
4 years ago
Evaluate the expressions 3x-2 and 4x+4 for the following value of x.
kirill [66]

Question:

Evaluate the expressions 3x - 2 and 4x + 4 for the following values of x. When you have found the value for each expression, write a statement using <, >, or = that shows how the two values are related. a. x = 0 b. x = -6 c. x = 5 d. x = -2

Answer:

Part a: 4x+4>3x-2

Part b: 4x+4=3x-2

Part c: 4x+4>3x-2

Part d: 4x+4>3x-2

Explanation:

Part a: Substituting x=0, we get,

\begin{aligned}3 x-2 &=3(0)-2 \\&=-2\end{aligned}

\begin{aligned}4 x+4 &=4(0)+4 \\&=4\end{aligned}

The value of 3x-2 is less than 4x+4

Thus, 4x+4>3x-2

Part b: Substituting x=-6, we get,

\begin{aligned}3 x-2 &=3(-6)-2 \\&=-18-2 \\&=-20\end{aligned}

\begin{aligned}4 x+4 &=4(-6)+4 \\&=-24+4 \\&=-20\end{aligned}

The value of 3x-2 and 4x+4 are equal.

Thus, 4x+4=3x-2

Part c: Substituting x=5, we get,

\begin{aligned}3 x-2 &=3(5)-2 \\&=15-2 \\&=13\end{aligned}

\begin{aligned}4 x+4 &=4(5)+4 \\&=20+4 \\&=24\end{aligned}

The value of 3x-2 is less than 4x+4

Thus, 4x+4>3x-2

Part d: Substituting x=-2, we get,

\begin{aligned}3 x-2 &=3(-2)-2 \\&=-6-2 \\&=-8\end{aligned}

\begin{aligned}4 x+4 &=4(-2)+4 \\&=-8+4 \\&=-4\end{aligned}

The value of 3x-2 is less than 4x+4

Thus, 4x+4>3x-2

4 0
3 years ago
Simplify (4x³)³<br> AND I OOP-
Readme [11.4K]

Answer:

It should be 64x^{9}

Step-by-step explanation:

4 0
3 years ago
Please help me I have this same class
Anastasy [175]
Uhhh where is it?.......
6 0
3 years ago
Solve for p2. p1v1 = p2v2
lukranit [14]

Answer:

P₂  = \frac{P_{1} V_{1}  }{V_{2} }  

Step-by-step explanation:

Given expression:

     Boyle's law:

             P₁ V₁   = P₂ V₂

Problem is to find P₂;

Solution:

              P₁ V₁   = P₂ V₂

 To solve this problem, multiply both sides by \frac{1}{V_{2} };

         

   P₁ V₁  x   \frac{1}{V_{2} }; = P₂ V₂  x  \frac{1}{V_{2} };

     \frac{1}{V_{2} } cancels out V₂ on the right hand side;

              P₂  = \frac{P_{1} V_{1}  }{V_{2} }  

6 0
3 years ago
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