How many $50 bills is found in $890
1 answer:
You might be interested in
Answer:
The solutions are correct
Step-by-step explanation:
i) In a year there is a total of 12 months, if ten students can have birthdays in 10 different months, the number of ways this can happen is:
Number of ways = 12 × 11 × 10 × . . . × 3 =
ii) The number of ways 1 student can have birthday months = 12¹, The number of ways 2 students can have birthday months = 12¹ × 12¹ = 12². Hence:
The number of ways 10 students can have birthday months = 12¹⁰
iii) The probability that no two share a birthday month = = 0.00387