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3 years ago

1/2x +1/3 y = 3

1 answer:

7 0

<span>C is the correct answer.
If you want to check it just divide both sides by six.
</span>3/6x + 2/6y = 18/6
1/2 + 1/3y = 3

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4. The constant of proportionality between the height of the water in a sink (h) in centimeters and the number of minutes it has

RUDIKE [14]

Answer:

i got 38

Step-by-step explanation:

6 0

3 years ago

What function equation is represented by the graph? f(x)=14x+3 f(x)=−4x−3 f(x)=−14x−3 f(x)=14x−3

Vladimir [108]

See the explanation

<h2>Explanation:</h2>

Remember you have to provide complete questions in order to get exact answers. Here I'll provide a general explanation, so:

<h3>First.</h3>

$f(x)=14x+3$

The slope is:

$m=14$

The y-intercept is:

$b=3$

By using graphing tool, we get the first graph shown below.

<h3>Second.</h3>

$f(x)=-4x-3$

The slope is:

$m=-4$

The y-intercept is:

$b=-3$

By using graphing tool, we get the second graph shown below.

<h3>Third.</h3>

$f(x)=-14x-3$

The slope is:

$m=-14$

The y-intercept is:

$b=-3$

By using graphing tool, we get the third graph shown below.

<h3>Fourth.</h3>

$f(x)=14x-3$

The slope is:

$m=14$

The y-intercept is:

$b=-3$

By using graphing tool, we get the fourth graph shown below.

<h2>Learn more:</h2>

Linear inequalities: brainly.com/question/12984296

#LearnWithBrainly

7 0

3 years ago

Read 2 more answers

I NEED HELP URGENTLY

tigry1 [53]

Answer:

30 square millimeters

Step-by-step explanation:

3 x 3 = 9

3 x 1 = 3

there are two sides with the area 9 therefore...

9 x 2 = 18

There are four sides with the area 3 therefore...

3 x 4 = 12

Therefore the suface area is

12 + 18 = 30

5 0

2 years ago

What distance would be covered in 60

ddd [48]

60 x 50 = 3000 meters.......

4 0

2 years ago

If L=√(x^2+y^2), dx/dt =-4, dy/dt=3, find dL/dt when x=4 and y=3

yulyashka [42]

Hello,

$L=\sqrt{x^2+y^2} \\\\\dfrac{dx}{dt}=-4\\\\\dfrac{dy}{dt}=3\\\\x=4, y=3\\\\\dfrac{\partial L} {\partial x} =\dfrac{x}{\sqrt{x^2+y^2}} \\\\\dfrac{\partial L} {\partial y} =\dfrac{y}{\sqrt{x^2+y^2}} \\\\\dfrac{dL}{dt} =\dfrac{\partial L} {\partial x}*\dfrac{dx}{dt}+\dfrac{\partial L} {\partial y}*\dfrac{dy}{dt}\\\\=-4*\frac{-4}{\sqrt{4^2+3^2}} +3*\frac{3}{\sqrt{4^2+3^2}}\\\\=\dfrac{16}{5} +\dfrac{9}{5} \\\\=5\\$

5 0

3 years ago