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bazaltina [42]
3 years ago
15

1/2x +1/3 y = 3

Mathematics
1 answer:
LekaFEV [45]3 years ago
7 0
<span>C is the correct answer.
If you want to check it just divide both sides by six.
</span>3/6x + 2/6y = 18/6
1/2 + 1/3y = 3
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Step-by-step explanation:

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3 years ago
what is the first term of a geometric sequence in which the second term is 6 and the fourth term is 54
IRISSAK [1]
For a geometric sequence:
U_{n} = a * r^{n - 1}
U_{n} = the nth term, i.e. U₂ is the second term, U₃ is the third term, etc.
a = first term (U₁)
r = multiplier
n = number corresponding to the postion of the nth term in the sequence, e.g. for U₂, n = 2, for U₃, n = 3

According to the information:
U₂ = 6
U₄ = 54
So:
U_{2} = a * r^{(2) - 1} = 6 \\\\ a * r^{1} = 6 \\\\ ar = 6 \\
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Now, we have two equations in terms of a and r;
We can work out a by first working out r;
If we let the U₂ eq'n be [1] and the U₄ eq'n be [2];
Then, we do [2] ÷ [1] to cancel out the a and get an equation with only r that we are able to solve and then just solve it, like so:
\frac{ar^{3}}{ar} =  \frac{54}{6} \\\\ r^{2} = 9 \\\\ r = 3
Note: r has to be 3, and not -3, as the two given terms of the sequence tell us that the terms of the sequence will get bigger from each term to the next so r has to be above 1.

Now that we know r, we can sub it back into either [1] or [2] and solve for a, Its quicker and easier to sub it into [1] as we have no powers greater than 1 and we have smaller numbers to deal with (but you would get the same value of a either way), so:
U₂ = ar = 6
a(3) = 6
a = 6/3
a = 2
5 0
3 years ago
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6 0
3 years ago
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Liula [17]
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8 0
3 years ago
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3 years ago
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