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3 years ago

Which table represents points on the graph of h(x) = RootIndex 3 StartRoot negative x + 2 EndRoot?

Mathematics

2 answers:

Evgen [1.6K]3 years ago

7 0

Answer:

Step-by-step explanation:

Alex_Xolod [135]3 years ago

3 0

Answer:

Table 3

Step-by-step explanation:

The third one.

We have the function

$h(x) = \sqrt[3]{-x+2}$

Now we will insert values of x in that definition o h(x) and see if the values we obtain match the corresponding y values in the table:

$h(-6) = \sqrt[3]{-(-6)+2}= \sqrt[3]{6+2}= \sqrt[3]{8} = 2\\h(1) = \sqrt[3]{-1+2}= \sqrt[3]{1}= 1\\h(2) = \sqrt[3]{-2+2}= \sqrt[3]{0}= 0\\h(3) = \sqrt[3]{-3+2}= \sqrt[3]{1}= 1\\h(10) = \sqrt[3]{-10+2}= \sqrt[3]{-8}= -2$

We can see that the values match the table 3, so the table 3 represents points on the graph of h(x)

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1. A 2012 survey conducted by the local paper in Columbus, Ohio one week before Election Day

mash [69]

Answer:

The description again for the problem is listed throughout the section below on explanations.

Step-by-step explanation:

A 2012 survey conducted a week since Voting day because the local paper in Columbus asked voters whatever individual they might vote for the state attorney. 37% of respondents said that they'd vote for both the dem candidate. In reality, 41 percent voted for both the Democratic nominee on Elections Day.

The 37% is supported by a survey as well as being a factual estimate. The sample proportion is denoted by "P". Therefore,

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The specific proportion becomes supplied as a factor of 41% = 0.41. Since the importance of proportion is real. The proportion of community is represented as p or π

Hence p = 0.41.

4 0

2 years ago

How many Solutions does this system have? (1 point)

mixas84 [53]

The given system of equation that is $2x+y=3$ and $6x=9-3y$ has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

$\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}$

Let us first bring the equation in standard form for comparison

$\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}$

$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

To check how many solutions are there for system of equations $a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0$ , we need to compare ratios of $\frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}$

In our case,

$a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3$

$a_{2} = 6, b_{2} = 3,\text{ and }c_{2} = -9$

$\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}$