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3 years ago

Which of these expressions is equivalent to m^2 - n^2 - 14n - 49?

Mathematics

1 answer:

polet [3.4K]3 years ago

6 0

Answer:

n = m - 7 or n = -m - 7

Step-by-step explanation:

Solve for n:

m^2 - (n + 7)^2 = 0

The left hand side factors into a product with two terms:

(-7 + m - n) (7 + m + n) = 0

Split into two equations:

-7 + m - n = 0 or 7 + m + n = 0

Subtract m - 7 from both sides:

-n = 7 - m or 7 + m + n = 0

Multiply both sides by -1:

n = m - 7 or 7 + m + n = 0

Subtract m + 7 from both sides:

Answer: n = m - 7 or n = -m - 7

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Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

$Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}$

Now the points A(−3, 4) and B(7, 2)

$AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}$

$AB = \sqrt{(10)^{2} +(-2)^{2}}$

$AB = \sqrt{100+4}$

$AB = \sqrt{104}$

$AB = 2\sqrt{26}\units$

Thus

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Now the points

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$AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}$

$AD = \sqrt{(-1)^{2} +(-5)^{2}}$

$AD = \sqrt{1 + 25}$

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$BC = \sqrt{26}\units$

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

$Length = 2\sqrt{26}\ units$

$Breadth = \sqrt{26}\ units$

$Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})$

$Perimeter\ of\ rectangle = 2(3\sqrt{26})$

$Perimeter\ of\ rectangle = 6\sqrt{26}$

$\sqrt{26} = 5.1 (Approx)$

$Perimeter\ of\ rectangle = 6\times 5.1$

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

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