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Neptune's distance from the sun is d₁ = 4.503 x 10⁹ km.
Mercury's distance from the sun is d₂ = 5.791 x 10⁷ km.
Calculate the number of times d₁ is greater than d₂.
Answer: 7.7759 x 10⁻¹ times
Mercury's distance from the sun is d₂ = 5.791 x 10⁷ km.
Calculate the number of times d₁ is greater than d₂.
Answer: 7.7759 x 10⁻¹ times
I've attached an image showing the coordinates of Ship A and Ship B.
Answer:
distressed vessel is located at (1, 1.5)
Step-by-step explanation:
From the image attached, we can see that;
Coordinate of ship A is (3, 4)
Coordinate of ship B is (1, 1)
Now, we are told that Ship A receives a distress signal from the southwest, and ship B receives a distress from the same vessel from the north.
This means that the distressed ship is somewhere in between ship A & B.
To solve this, we will extend the arrow line from Ship A in that same SW direction and we will do the same for ship B in the same North direction. Their point of intersection is where the distressed ship is located.
Now, if we do that, we will see that they will intersect at the point; (1, 1.5)
Thus,distressed vessel is located at (1, 1.5)
