Answer:
I attached a pic of my work, its 100% correct.
Its a bit messy....
Answer: tell him " your way doesnt work many people have the same issue so im doing it my way"
Step-by-step explanation:thats job done
Answer:
5.264 * 10^4
Step-by-step explanation:
We put a decimal point to the right of the number, so
52640.
Then we move it to the left until we get a number that is between 1 and 10.
5.2640
This was four hops to the left.
We can remove the trailing 0, and write
5.264 * 10^4
10^4 because of the four hops
Answer:
Step-by-step explanation:
1)
O = center of circle (origin)
we know that the angle at the center of the circle ∠ ROS will be
180= 2(31) + ∠x
180-62 = ∠x
118° = ∠x
The supplemental angle to the 118° will be 62°
62° is the interior angle to arc QR , so
arc QR is also 62°
3)
b/c the intercepted arc YZ = 2* 68=136
then 136+125+? = 360
? = 99°
arc ZX = 99°
5)
O= center point
we are given the two arcs 120 and 70 for both of these we know that the
interior angles will be the same. ∠JOX has a central angle of 120 , then
b/c triangle JOX is an isosceles, we know that the two angles J and X of
the triangle JOX will be 1/2 of 60 , or 30 each
also for
also ∠XOY has an interior angle of 70 so the two angle at X and Y will be 1/2 of 110 , or 55°
now add 55+30 to find X for box XYZJ
85° = ∠X
![A = A_{0}*( \frac{1}{2})^(t/t_{\frac{1}{2}) [tex]A= Amount of Substance Left A_{0} = Initial Amount of Substance t = Time Taken t_{\frac{1}{2}} = Half-Life of the Substance](https://tex.z-dn.net/?f=A%20%3D%20A_%7B0%7D%2A%28%20%5Cfrac%7B1%7D%7B2%7D%29%5E%28t%2Ft_%7B%5Cfrac%7B1%7D%7B2%7D%29%20%20%5Btex%5DA%3D%20Amount%20of%20Substance%20Left%20A_%7B0%7D%20%3D%20Initial%20Amount%20of%20Substance%20t%20%3D%20Time%20Taken%20t_%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20Half-Life%20of%20the%20Substance)