Write the recursive formula for -34, -38, -42, -46, -50 ...

Mathematics

1 answer:

Alex787 [66]3 years ago

8 0

Answer:

-30 - 4n

Step-by-step explanation:

-34, -38, -42, -46, -50 ...

the sequence first term is -34

a= -34

Common difference (d) = T2 - T1 = T3 - T2

d = -38- -34 = -42 - - 38 = -38+34

d = -4

Formula for nth term

Tn = a + (n-1)d

Tn = -34 + (n -1)-4

Tn = -34 -4n + 4

Tn = -30 - 4n

= -30 - 4n

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Step-by-step explanation:

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$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot 5^{x-4}\\\\5^{x-2}-11\cdot 5^{x-4}=7^{x-3}+7^{x-5}\\\\5^{x-2}(1-11\cdot 5^{-2})=7^{x-3}(1+7^{-2})\\\\5^{x-2}\dfrac{14}{25}=7^{x-3}\dfrac{50}{49}\\\\1=\dfrac{2\cdot 7^{x-3}5^4}{2\cdot 5^{x-2}7^3}=\left(\dfrac{7}{5}\right)^{x-6}\\\\0=(x-6)\log(1.4)\\\\x=6$