This is an incomplete question, here is a complete question and image is also attached below.
How much longer is the hypotenuse of the triangle than its shorter leg?
a. 2 ft
b. 4 ft
c. 8 ft
d. 10 ft
Answer : The correct option is, (b) 4 ft
Step-by-step explanation:
Using Pythagoras theorem in ΔACB :


Given:
Side AC = 6 ft
Side BC = 8 ft
Now put all the values in the above expression, we get the value of side AB.



Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.
Difference = Side AB - Side AC
Difference = 10 ft - 6 ft
Difference = 4 ft
Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.
Solution:
The probability of an event is expressed as

In a pack of 52 cards, we have

Thus, we have the probability to be evaluated as
Answer:
x=-3
Step-by-step explanation:
7x=-13-8
7x=--21
x=-21/7
x=-3
points or brainleist please
Answer:
4 feet
Step-by-step explanation:
We start by subtracting the 6 from the 14, to get the leftover space on the wall, 8 feet. We then divide that by two, since if the painting is centered there will be two equally-sized spaces on either side of it. This means that X = 4 feet.
Y=mx+b, m= slope, b= y intercept, plug in. Y=3x+5