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Alchen [17]
3 years ago
9

Hey can you please help me posted picture of question

Mathematics
1 answer:
vfiekz [6]3 years ago
5 0
Common factor is such a term which can be taken out common from each term of the expression.

If you observe the given expression, 2x can be taken out common leaving the expression which cannot be factored any further.

14x² - 12x
= 2x (7x - 6)

So 2x is the common factor. The answer to this question is option C
You might be interested in
Graph these equations: y=x+5 y=x–3 Click to select points on the graph.
yaroslaw [1]

Answer:

y=x+5 graph points: (0,5), (-5,0)

y=x-3 graph points: (0,-3), (3,0)

Step-by-step explanation:

These equations are in slope-intercept form.

y=mx+b

m=slope

y= y-intercept

I graphed the lines based on the equations and gave the two points of each equation where the line intersected the x and y axis.

<em>Hope this helped! Brainliest would be great :)</em>

6 0
3 years ago
In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 3.0 m/s up a 22.0° inclined track
Aloiza [94]

Answer:

Approximately 0.31\; \rm m, assuming that g = 9.81\; \rm N \cdot kg^{-1}.

Step-by-step explanation:

Initial kinetic energy of the sled and its passenger:

\begin{aligned}\text{KE} &= \frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2} \times 14\; \rm kg \times (3.0\; \rm m\cdot s^{-1})^{2} \\ &= 63\; \rm J\end{aligned} .

Weight of the slide:

\begin{aligned}W &= m \cdot g \\ &= 14\; \rm kg \times 9.81\; \rm N \cdot kg^{-1} \\ &\approx 137\; \rm N\end{aligned}.

Normal force between the sled and the slope:

\begin{aligned}F_{\rm N} &= W\cdot  \cos(22^{\circ}) \\ &\approx 137\; \rm N \times \cos(22^{\circ}) \\ &\approx 127\; \rm N\end{aligned}.

Calculate the kinetic friction between the sled and the slope:

\begin{aligned} f &= \mu_{k} \cdot F_{\rm N} \\ &\approx 0.20\times 127\; \rm N \\ &\approx 25.5\; \rm N\end{aligned}.

Assume that the sled and its passenger has reached a height of h meters relative to the base of the slope.

Gain in gravitational potential energy:

\begin{aligned}\text{GPE} &= m \cdot g \cdot (h\; {\rm m}) \\ &\approx 14\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times h\; {\rm m} \\ & \approx (137\, h)\; {\rm J} \end{aligned}.

Distance travelled along the slope:

\begin{aligned}x &= \frac{h}{\sin(22^{\circ})} \\ &\approx \frac{h\; \rm m}{0.375}\end{aligned}.

The energy lost to friction (same as the opposite of the amount of work that friction did on this sled) would be:

\begin{aligned} & - (-x)\, f \\ = \; & x \cdot f \\ \approx \; & \frac{h\; {\rm m}}{0.375}\times 25.5\; {\rm N} \\ \approx\; & (68.1\, h)\; {\rm J}\end{aligned}.

In other words, the sled and its passenger would have lost (approximately) ((137 + 68.1)\, h)\; {\rm J} of energy when it is at a height of h\; {\rm m}.

The initial amount of energy that the sled and its passenger possessed was \text{KE} = 63\; {\rm J}. All that much energy would have been converted when the sled is at its maximum height. Therefore, when h\; {\rm m} is the maximum height of the sled, the following equation would hold.

((137 + 68.1)\, h)\; {\rm J} = 63\; {\rm J}.

Solve for h:

(137 + 68.1)\, h = 63.

\begin{aligned} h &= \frac{63}{137 + 68.1} \approx 0.31\; \rm m\end{aligned}.

Therefore, the maximum height that this sled would reach would be approximately 0.31\; \rm m.

7 0
2 years ago
the gasoline gauge on a van initially read 1/8 full. When 15 gallons were added to the tank, the gauge read 3/4 full. how many m
nexus9112 [7]
Let x be the capacity of the tank then
3x/4-x/8 =15,
then x=24, so so far it has 3/4 *24 =18 so you need 6 gallons to fill it up
5 0
3 years ago
How do you divide big numbers?<br>like for example, 2,673 ÷ 486?
Dahasolnce [82]
The easiest way I know is to multiply the divisor by different numbers to see how many times it will go into the dividend. multiplying 486 by 2 or three and seeing which one gets closest.
3 0
3 years ago
Please answer correctly !!!!!!!!!! Will mark brainliest !!!!!!!!!!!!
Drupady [299]

Answer:

6

Step-by-step explanation:

f(6) = -6   this is the value when the x value is 6

g(5) = -5 this is the value when the x value is 5

4 * f(6) -6*g(5)

4*-6 - 6* -5

-24 + 30

6

5 0
3 years ago
Read 2 more answers
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