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alukav5142 [94]

3 years ago

9

A population of flies, P, over a given amount of time, x, is modeled by the expression

1 answer:

ra1l [238]3 years ago

7 0

Do you know what you are suppose to do first

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Complete the pattern 650 6.5

Allushta [10]

I think the next one is,65.0

6 0

3 years ago

Read 2 more answers

Factor by first factoring out the greatest comImon factor 15x-55x 20

Bingel [31]

Answer:

Greatest common factor is 5

Step-by-step explanation:

5 goes into each of the coefficients.

6 0

3 years ago

Solve this question with Statements and reasoning.

qaws [65]

Here

$\\ \sf\longmapsto PD\cong PC$

As

P is the midpoint of AC and BD

$\\ \sf\longmapsto AC=BD$

$\\ \sf\longmapsto AP+PC=PD+BP$

Put PD=PC

$\\ \sf\longmapsto AP+PC=PC+PB$

Cancel PC

$\\ \sf\longmapsto AP=BP$ (Proved)

4 0

3 years ago

What is the inverse of f (x) = x-8/3

liq [111]

Answer:

Step-by-step explanation:

Since g(f(x))=x g ( f ( x ) ) = x , f−1(x)=3√x+8 f - 1 ( x ) = x 3 + 8 is the inverse of f(x)=(x−8)3 f ( x ) = ( x - 8 ) 3 .

5 0

2 years ago

Find the sum of the first 8 terms of the following series, to the nearest integer.

motikmotik

Answer:

The sum of the first 8 terms will be:

$\frac{1288991}{7776}$

Step-by-step explanation:

Given the sequence

$36, 30, 25, ...$

A geometric sequence has a constant ratio and is defined by

$a_n=a_0\cdot r^{n-1}$

computing the common ratio

$\frac{30}{36}=\frac{5}{6},\:\quad \frac{25}{30}=\frac{5}{6}$

$r=\frac{5}{6}$

As the first element is

$a_1=36$

so the nth term will be:

$a_n=a_0\cdot r^{n-1}$

$a_n=36\left(\frac{5}{6}\right)^{n-1}$

Geometric sequence sum formula

$a_1\frac{1-r^n}{1-r}$

Plugin the values to determine the sum of the first 8 terms

$n=8,\:\spacea_1=36,\:\spacer=\frac{5}{6}$

$=36\cdot \frac{1-\left(\frac{5}{6}\right)^8}{1-\frac{5}{6}}$

$=\frac{\left(1-\left(\frac{5}{6}\right)^8\right)\cdot \:36}{1-\frac{5}{6}}$

$=\frac{36\left(-\left(\frac{5}{6}\right)^8+1\right)}{\frac{1}{6}}$

$=\frac{36\left(-\frac{390625}{1679616}+1\right)}{\frac{1}{6}}$

$=\frac{\left(1-\frac{390625}{1679616}\right)\cdot \:36\cdot \:6}{1}$

$=\frac{216\left(-\frac{390625}{1679616}+1\right)}{1}$

$=\frac{216\cdot \frac{1288991}{1679616}}{1}$

$=216\cdot \frac{1288991}{1679616}$

$=\frac{1288991\cdot \:216}{1679616}$

$=\frac{278422056}{1679616}$

$=\frac{1288991}{7776}$

Therefore, the sum of the first 8 terms will be:

$\frac{1288991}{7776}$

7 0

3 years ago