1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alukav5142 [94]
3 years ago
9

A population of flies, P, over a given amount of time, x, is modeled by the expression

Mathematics
1 answer:
ra1l [238]3 years ago
7 0
Do you know what you are suppose to do first

You might be interested in
Lila uses craft sticks to make stars for an art project. She uses 5 craft sticks for each star,and she has 19 craft sticks. Lila
Savatey [412]

Answer:

3

Step-by-step explanation:

5×3=15 she would have 4 left but can't make a full star

7 0
3 years ago
A company developing a new cellular phone plan intends to market their new phone to customers who use text and social media ofte
Ber [7]

Answer:

A customer who sends 78 messages per day would be at 99.38th percentile.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Average of 48 texts per day with a standard deviation of 12.

This means that \mu = 48, \sigma = 12

a. A customer who sends 78 messages per day would correspond to what percentile?

The percentile is the p-value of Z when X = 78. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 48}{12}

Z = 2.5

Z = 2.5 has a p-value of 0.9938.

0.9938*100% = 99.38%.

A customer who sends 78 messages per day would be at 99.38th percentile.

8 0
3 years ago
What is a hoax and what is its purpose?
kotegsom [21]
A hoax is a deception. A hoax is used to deceive people.
6 0
3 years ago
What is the value of the expression below when z =<br> 6?<br> z² + 32-3
professor190 [17]

Answer:

65

Step-by-step explanation:

z=6

1) 6*6=36

2) 36+32=68

3) 68-3=65

5 0
3 years ago
Either enter an exact answer in terms of \piπpi or use 3.14, point, 14 for \piπpi and enter your answer as a decimal.
OverLord2011 [107]

Answer:

49π sq. units

Step-by-step explanation:

Find the diagram attached

We can find the area of the given circle

Given

diameter of the circle d = 14

Area of the circle = πd²/4

Substitute the given diameter

Area of the circle = π(14)²/4

Area of the circle = 196π/4

Area of the circle = 49π sq. units

Hence the exact answer in terms of π is 49π sq. units

4 0
3 years ago
Other questions:
  • Always remember... LOVE IS LOVE &lt;3
    11·2 answers
  • Jenny had 3 5/10 cakes. A) if she split each cake up into parts that were 2/5 of a piece of a cake in size, then how many of tho
    11·1 answer
  • 7. Write the equation of the line that passes through the
    7·1 answer
  • A coat is on sale for 65% of the original price of $58. Calculate the sale price. Explain please
    9·2 answers
  • Greg has $250 to spend. He wants to buy a new gaming system that is usually $380 but he knows it is on sale. If there is an 8% s
    8·1 answer
  • Each table in a banquet room seats 8 people. The room can seat no more than 360 people. Write and solve an inequality to represe
    11·1 answer
  • Please In Need of HELP
    14·1 answer
  • I’ll give you Brainliest
    8·2 answers
  • 100 students were surveyed. Of those surveyed, 60% said they had a sister. Of that group, 30% also had a brother. Of the student
    12·1 answer
  • HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!