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algol13
3 years ago
9

(1/2)^(x-3) = (1/4)^(x-5) Solve for x using logs

Mathematics
1 answer:
inn [45]3 years ago
5 0
(X-3)*log(1/2)=(x-5)*log(1/4)
X-3=(log(1÷4)÷log(1÷2))*(x-5)
X-3=2(x-5)
X-3=2x-10
X-2x=3-10
-x=-7
X=7
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8 The graph of y = a cos(x + b) for 0 2<br> 1<br> 60<br> 120<br> 180<br> 240<br> 300<br> 360<br> -1<br> -2<br> (a) Find the valu
MAVERICK [17]

Answer:

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8 0
2 years ago
How do I solve this?
Tanya [424]
Y=-3x+5 hope this helps
3 0
3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
PLEASE SOMEONE PLEASE HELP ME
Monica [59]

Answer:

- 5

Step-by-step explanation:

Jdkdkekekeo

7 0
3 years ago
Read 2 more answers
HELP!!!!!!!!! I’m almost done
balandron [24]

Alright, we're in the home stretch here :) All you need to remember is that i² = -1. Otherwise, it is the same as FOIL


(3-2i)(1+7i)

3-2i+21i-14i² ← Replace the i² with -1, then simplify like numbers

3+19i+14

17+19i or C

8 0
3 years ago
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