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Neporo4naja [7]
3 years ago
5

What is the area of a sector with a central angle of 8 π/11 radians and a radius of 7.2 ft? use 3.14 for π and round your final

answer to the nearest hundredth. enter your answer as a decimal in the box.
this is just to help any of my fellow people who suck at math :)

Mathematics
1 answer:
coldgirl [10]3 years ago
7 0

Answer:

59.19 ft^2

Step-by-step explanation:

step 1

Find the area of the circle

The area of the circle is equal to

A=\pi r^{2}

we have

r=7.2\ ft

\pi =3.14

substitute

A=(3.14)(7.2)^{2}

A=162.78\ ft^2

step 2

we know that

The area of a circle subtends a central angle of 2π radians

so

using proportion

Find out the area of a sector with a central angle of 8 π/11 radians

\frac{162.78}{2\pi }\frac{ft^2}{rad} =\frac{x}{(8\pi/11)}\frac{ft^2}{rad} \\\\x=162.78(8/11)/2\\\\x=59.19\ ft^2

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LenKa [72]

Answer:

I'm not sure what you want me to answer from this, so I solved for every variable:

Angle A: 83°

Side b: 6.29

Side c: 5.8

Step-by-step explanation:

-----Angle A:

Since the sum of the interior angles of a triangle ALWAYS equal 180°, we can solve for angle A as follows:

A+51+46=180\\A+97=180\\A=83

-----Side b:

Here, we use the sin rule for finding sides, since we know all of the angles as well as one side:

\frac{a}{sin(A)} =\frac{b}{sin(B)} \\\frac{8}{sin(83)} =\frac{b}{sin(51)} \\8.06=\frac{b}{0.78} \\6.29=b

-----Side c:

\frac{a}{sin(A)} =\frac{c}{sin(C)} \\\frac{8}{sin(83)}=\frac{c}{sin(46)} \\8.06=\frac{c}{0.72} \\5.8=c

7 0
2 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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3 years ago
What is the common difference of 80,60,45,33.75
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Answer:

The common difference (or common ratio) = 0.75

Step-by-step explanation:

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ii) let the second term be a_{2}  = a_{1} . r = 80 × r = 60      ∴  r = \frac{60}{80} = 0.75

iii) let the third term be     a_{3}  = a_{2} . r = 60 × r = 45      ∴  r = \frac{45}{60} = 0.75

iv) let the fourth term be   a_{4} = a_{3} . r = 45 × r = 33.75   ∴ r = \frac{33.75}{45} = 0.75

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So first step is to simplify everything outside of the radicals.
6*2=12
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Now we know that
__ __ __
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And
__ __
\| 2 * \| 2 = 2

And
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So if we incorporate what we know into the equation, we can figure it out.
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Now by simplifying the radical four and combining the radical twos, we can get all whole numbers.
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