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3 years ago

Find the area of the or rectangle square. 15 in and 12in

Mathematics

2 answers:

Elza [17]3 years ago

6 0

Multiply the length and the width giving you 180

Vanyuwa [196]3 years ago

4 0

Multiply the length by the width. so 15x12=180 inches.

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Find the product (-3/5) (-2/9)

Temka [501]

I think the answer is 2/15

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3 years ago

Read 2 more answers

Write an equation for the following tile pattern. Figure 2 Figure 3 Figure 4

oksano4ka [1.4K]

Answer:

The general equation following the pattern becomes is 7 + (n - 1)×2

Where, n = The figure number - 1

Step-by-step explanation:

The pattern in the question can be described as follows;

Figure 2 = (5 + 2) squares boxes = 7 squares boxes

Figure 3 = (5 + 2 + 2) squares boxes

Figure 4 = (5 + 2 + 2 + 2) squares boxes

Therefore, the number of squares boxes per figure, form an arithmetic progression (a + (n - 1)d) with the first term a = 7, the common difference d = 2, and the n = the nth term of the series, such that the general equation following the pattern becomes;

7 + (n - 1)×2.

3 0

3 years ago

If the measure of angle BDC=100°, measure of angle A = 50°, and measure of angle DBC= 30°. which statement is true?

expeople1 [14]

B. triangle ABC is isosceles. The angles add up 180 degrees.

7 0

3 years ago

X = ? y = ? 16 45 degrees

mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

For y, we will be using the Sine Function.

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

5 0

1 year ago

A carpenter makes wooden chairs.

monitta

Answer:

Is there supposed to be a graph somewhere?

8 0

3 years ago