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1 year ago

Please help me out it doesn’t have to be the hole page but please help!:(

Mathematics

1 answer:

77julia77 [94]1 year ago

6 0

You're going to have to take a better quality picture. I don't think anyone can reliably read any of that

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Three high school participated in a study to evaluate the effectiveness of a new computer-based mathematics curriculum. Four 24-

snow_tiger [21]

Answer:

A) experimental

B) The important factors are : Type of instruction, scores and High schools,

The factor levels are :

Level -1 which comprises of 3 highschool,

Level -2 which comprises of highschool and the highschool has 4 sections and each section has 24 students

Factor level combinations:

Level 1 : computer and standard based combination

C) Within the subject : 24 students

Between subject : High school

D) score of the test

E) student

Step-by-step explanation:

A) The study is experimental because of the random assignment of two different types of instruction to the students which will control/affect the technique of teaching without just observing the performance of the students from the side

B) The important factors are : Type of instruction, scores and High schools,

The factor levels are :

Level -1 which comprises of 3 highschool,

Level -2 which comprises of highschool and the highschool has 4 sections and each section has 24 students

Factor level combinations:

Level 1 : computer and standard based combination

C) Within the subject : 24 students

Between subject : High school

D) The dependent measure is the score of the test

E) The basic experiment unit of the study is : student

8 0

3 years ago

Solve the following equation. Only enter the numeric answer (no variables). 30=2.5(10-2x)

yKpoI14uk [10]

Answer:

x = -1

Step-by-step explanation:

30 = 2.5(10)(-2x) - you multiply by each

30 = 25 - 5x - then pass 25 to the other side and subract

5x = - 5x - then divide 5 / -5

x = -1 - and you have the answer

7 0

3 years ago

Read 2 more answers

How derivative of this absolute value function is like this!

Daniel [21]

Recall the definition of absolute value.

$|x| = \begin{cases} x & \text{if } x \ge 0 \\ -x & \text{if } x < 0 \end{cases}$

When $x$ ,

$|x| = x \implies \dfrac{d|x|}{dx} = 1$

When $x$ ,

$|x| = -x \implies \dfrac{d|x|}{dx} = -1$

The derivative does not exist at $x=0$ , since the one-sided limits

$\displaystyle \lim_{x\to0^-} f'(x) = -1$

and

$\displaystyle \lim_{x\to0^+} f'(x) = +1$

do not match.

So the derivative of $|x|$ is

$\dfrac{d|x|}{dx} = \begin{cases} 1 & \text{if } x > 0 \\ -1 & \text{if } x < 0 \\ \text{undefined} & \text{if } x = 0\end{cases}$

Now we can write this as

$\dfrac{d|x|}{dx} = \dfrac x{|x|} = \dfrac{|x|}x$

since

$x > 0 \implies |x| = x \implies \dfrac{|x|}x = \dfrac xx = 1$

and

$x < 0 \implies |x| = -x \implies \dfrac{|x|}x = -\dfrac xx = -1$

6 0

1 year ago

The sum of aanual interest and semi-annual compound interest on a sum of money for 2 years at the interest rate of 20% per annum

Serggg [28]

hmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

3 0

2 years ago

How to factorise? I need to factorise 4a^2 - 12b please show method

Lubov Fominskaja [6]

4a² - 12b = 4 (a² - 3b)
so you just pull out the common factor between the two term 4
then you divide each term by the common factor to find what remain
4a²/4 = a²
-12b/4= -3b
so now you put the four as the multiplier outside of the bracket and then put back the remainders: 4 ( a² - 3b)

7 0

3 years ago