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3 years ago

Jack is 2 times as old as lacy.6 years ago the sum of the age was 21.how old are they now

Mathematics

1 answer:

Setler79 [48]3 years ago

6 0

If I didn’t make a mistake it would make him 54

Hope this helps

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F(x)=-4x+9 g(x)=-3x^2+5x+9, Find f(x)•g(x)

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3 years ago

36. The price of a new home. According to the U.S. Census

zmey [24]

Answer:

210

Step-by-step explanation:

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3 years ago

Help please!!!!!!!!!!!!!!

Lapatulllka [165]

Answer:

3(n + 2) > 0

Step-by-step explanation:

Work on a piece at a time.

"sum of a number and two": n + 2

"three times the sum of a number and two": 3(n + 2)

"three times the sum of a number and two is greater than zero": 3(n + 2) > 0

Answer: 3(n + 2) > 0

5 0

3 years ago

A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the n

Ratling [72]

Answer:

$k = \dfrac{1}{21}$

b) 0.476

c) 0.667

Step-by-step explanation:

We are given the following in the question:

Y = the number of forms required of the next applicant.

Y: 1, 2, 3, 4, 5, 6

The probability is given by:

$P(y) = ky$

a) Property of discrete probability distribution:

$\displaystyle\sum P(y_i) = 1\\\\\Rightarrow k(1+2+3+4+5+6) = 1\\\\\Rightarrow k(21) = 1\\\\\Rightarrow k = \dfrac{1}{21}$

b) at most four forms are required

$P(y \leq 4) = \displaystyle\sum^{y=4}_{y=1}P(y_i)\\\\P(y \leq 4) = \dfrac{1}{21}(1+2+3+4) = \dfrac{10}{21} = 0.476$

c) probability that between two and five forms (inclusive) are required

$P(2\leq y \leq 5) = \displaystyle\sum^{y=5}_{y=2}P(y_i)\\\\P(2\leq y \leq 5) = \dfrac{1}{21}(2+3+4+5) = \dfrac{14}{21} = 0.667$

8 0

3 years ago