solve for x.
4x−5=7+4y
Add 5 to both sides.
4x−5+5=4y+7+5
4x=4y+12
Divide both sides by 4.
4x/4=4y+12/4
x=y+3
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Answer:
Step-by-step explanation:
Combine real terms and combine complex terms
1) 3 + 2i + 2 - 5i = 3 +2 + 2i - 5i
= 5 + (2-5)i
= 5 + (-3)i
= 5 - 3i
3) 2 - (1 - 2i) + (4 -5i ) - (1 - 3i) = 2 -1 + 2i + 4 - 5i - 1 + 3i
{- is distributed to (1 - 2i) & - is distributed to (1- 3i)}
= 2 - 1 + 4 + 1 + 2i - 5i + 3i
= 6 +0i = 6
5) 4 - 3i + 4 + 3i = 4 +4 -3i + 3i
= 8
7) (3 - 2i)² + (3 +2i) = 3² - 2*3*2i + (2i)² + 3 + 2i {(a - b)² = a² - 2ab +b²}
= 9 -12i + 4i² + 3 + 2i
= 9 - 12i + 4*(-1) + 3 + 2i {i² = -1}
= 9 +3 - 4 - 12i +2i
= 8 - 10i
Answer:
Inverse Property of Addition (Reason C)
Step-by-step explanation:
<u>Given:</u> 3(x – 4) = 33
<u>Prove: </u>x = 15
Statements Reasons
1. 3(x – 4) = 33 Given
2. 3x – 12 = 33 Distributive Property (Reason A)
3. 3x – 12 + 12 = 33 + 12 Addition Property of Equality (Reason B)
4. 3x + 0 = 45 Inverse Property of Addition (Reason C)
5. 3x = 45 Zero Addition Property (Reason D)
6. x = 15 Division Property of Equality
The correct answer is option B.
From the graph we can see the following discontinuities:
a) A hole at x = -2
b) A jump at x = 0
c) A hole at x = 8
The hole refers to the point discontinuity and the jump refers to as jump discontinuity. The function is defined and is continuous at x = 3
Thus, the given graph has jump discontinuity at x = 0 and point discontinuity at x = -2 and x = 8
