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Dvinal [7]
3 years ago
13

In AKLM, KM is extended through point M to point N,

Mathematics
2 answers:
aksik [14]3 years ago
8 0

Answer:

3#6#8#9%8$%8&jlebsiei lebsosbe he is yes

JulsSmile [24]3 years ago
6 0

Answer: 6

Step-by-step explanation:

I need point

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Maria measured a centipede that was 1 1/12 inches long. Jerome measured a centipede that was 11/12 of an inch long. How much lon
4vir4ik [10]

Answer:

1/6

Step-by-step explanation:

The centipede that Maria measured was 1 1/12 inches long. If you convert this to an improper fraction it is equal to 13/12 inches. Now to find how much longer Maria's centipede was than Jeromes, you just take 11/12 and minus it from 13/12 which is equal to 2/12 of an inch, which then simplifies to 1/6 of an inch.

3 0
2 years ago
F(x)= -2(x-5)^2+8
geniusboy [140]
I don’t know all of it but....
Axis of symmetry is x=5
Vertex changed to (5,8)
Parabola opens down
4 0
3 years ago
What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C

Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

Interval [0, π]

<u>Step 2: Find Arc Length</u>

  1. [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:         \displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.
  2. Substitute in variables [Arc Length Formula - Parametric]:                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx
  3. [Integrand] Simplify:                                                                                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx
  4. [Integral] Evaluate:                                                                                         \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0
2 years ago
If y is the circumcenter is angle STU find each measure
snow_tiger [21]

Answer:

Measures are SV=9 units., SY=14 units, YW=\sqrt75units , YW=\sqrt27units

Step-by-step explanation:

Given Y is the circumcenter of ΔSTU. we have to find the measures SV, SY, YW and YX.

As Circumcenter is equidistant from the vertices of triangle and also The circumcenter is the point at which the three perpendicular bisectors of the sides of the triangle meet.

Hence, VY, YW and YX are the perpendicular bisectors on the sides ST, TU and SU.

Given ST=18 units.

As VY is perpendicular bisector implies SV=9 units.

Also in triangle VTY

YT^{2}=VY^{2}+VT^{2}

⇒ 14^{2}=VY^{2}+9^{2}

⇒ VY^{2}=115

As vertices of triangle are equidistant from the circumcenter

⇒ SY=YT=UY=14 units

Hence, SY is 14 units

In ΔUWY, UY^{2}=YW^{2}+UW^{2}

⇒ 14^{2}=YW^2+11^{2}

⇒ YW^2=196-121=75 ⇒ YW=\sqrt75units

In ΔYXU, UY^{2}=YX^{2}+XU^{2}

⇒ 14^{2}=YX^2+13^{2}

⇒ YX^2=196-169=27 ⇒ YW=\sqrt27units

Hence, measures are SV=9 units., SY=14 units, YW=\sqrt75units , YW=\sqrt27units





4 0
3 years ago
Please help guys much love
lord [1]

Step-by-step explanation:

1) Ans 3

2) Ans 6

3) Ans 4

4) Ans 1/5

5) Ans 1/23

4 0
2 years ago
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