A farmstand sells two types of grapes. the cost of green grapes can be represented by the equation Y= 1.5X, where Y is the total
cost for X pounds. the graph represents the cost of black grapes which statement must be true?
A. Three pounds of green grapes cost $6.00.
B. Black grapes cost less per pound than green grapes l.
C. Black grapes cost more per pound than green grapes.
D. Two pounds of black grapes cost $3.00.
PLEASEEEE HELP
A. Three pounds of green grapes cost $6.00.
B. Black grapes cost less per pound than green grapes l.
C. Black grapes cost more per pound than green grapes.
D. Two pounds of black grapes cost $3.00.
PLEASEEEE HELP
1 answer:
You might be interested in
Answer:
a) Interest earned = $36
New Balance = $336
b) Interest rate = 0.05 or 5%
New Balance = $517.5
c) time t = 5
New Balance = $612.5
d) Principal Amount = $675
New Balance = $783
Step-by-step explanation:
We are given:
a) Principal (P) = $300
Rate (r) = 3% or 0.03
Time (t)= 4 years
Interest earned = ?
The formula used is:
Putting values and finding interest
So, Interest earned = $36
New Balance = Principal + Interest = 300+36 = $336
b) a) Principal (P) = $300
Rate (r) = ?
Time (t)= 3 years
Interest earned = 67.50
The formula used is:
Putting values and finding rate
So, Interest rate = 0.05 or 5%
New Balance = Principal + Interest = 450+67.50 = $517.5
c) Principal (P) = $500
Rate (r) = 4.5% or 0.045
Time (t)= ?
Interest earned = $112.50
The formula used is:
Putting values and finding time
So, time t = 5
New Balance = Principal + Interest = 500+112.50 = $612.5
d) Principal (P) = ?
Rate (r) = 8% or 0.08
Time (t)= 2 years
Interest earned = 108.00
The formula used is:
Putting values and finding Principal
So, Principal Amount = $675
New Balance = Principal + Interest = 675+108 = $783
Answer:
For a mean oil change time of 20.51 minutes there would be a 10% chance of being at or below
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
Treating this as a random sample, at what mean oil-change time would there be a 10% chance of being at or below?
This is the 10th percentile, which is X when Z has a pvalue of 0.1. So it is X when Z = -1.28.
By the Central Limit Theorem
For a mean oil change time of 20.51 minutes there would be a 10% chance of being at or below