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Strike441 [17]
3 years ago
8

HELPPP PLEASEE l

Mathematics
1 answer:
daser333 [38]3 years ago
6 0

Answer:

Car M:

50.4/2 = 25.2

car M uses up 1 gallon every 25.2 miles

Car P:

Just from the graph, you can see that it uses up 1 gallon every 30 miles

The two graphs vary the /miles slightly but it is around their zones of 25.2 and 30. It varies slightly because the cars may be traveling at a fast speed or slower speed thus using up more or less fuel by the time they've reached the recorded distances on the graphs.

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PLZ HELP ill GIVE BRAINIESt!!!!20 Points
Semmy [17]
HOPE YOU CAN READ THE EXCEL FILE
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4 0
3 years ago
Isabelle bought a new mountain bike for $1,149.79. She will finish paying for the bike after 6 months. Each month, she will pay
Leto [7]
B.200 because 200x6 is 1200 and 100 is to little and 250 is too much so it’s b.
6 0
3 years ago
Solve for q.<br><br> 3/5 = q/10<br><br> q=?
Helga [31]
Simply the equation by using cross-multiplication, you get 30=5q
Then you swap sides of the equation, you get 5q=30
Then you divide both sides of the equation by 5
Your answer is q=6
4 0
3 years ago
The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units
ad-work [718]
Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&A&(~ 2 &,& 8~) &#10;%  (c,d)&#10;&C&(~ 6 &,& 2~)&#10;\end{array}~~~ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}&#10;\\\\\\&#10;AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}&#10;\\\\\\&#10;AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&A&(~ 2 &,& 8~) &#10;%  (c,d)&#10;&B&(~ 16 &,& 2~)&#10;\end{array}\\\\\\&#10;AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}&#10;\\\\\\&#10;AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}&#10;\\\\\\&#10;AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}

so, add AC + AB + CB, and that's the perimeter of the triangle.

8 0
3 years ago
PLZ HELP WORTH A LOT OF POINTS AND I HAVE 10 MINUTES!!!!
Lina20 [59]

Answer:

The area after 9 years will be 1,234 km^2

Step-by-step explanation:

In this question, we are tasked with calculating what the area of a certain forest that decreases at a certain percentage would be after some years.

To answer this question, we shall be using an exponential approximation.

Now, to use this exponential approximation, we shall be needing a supporting exponential mathematical equation.

This can be written as;

A = I(1-r)^t

where A is the new area we are looking for

I is the initial area which is 1700 according to the question

r is the rate of decrease which is 3.5% = 3.5/100 = 0.035

t is time which is 9 years according to the question

We plug these values and have the following;

A = 1700(1-0.035)^9

A = 1700(0.965)^9

A = 1,233.66

This is 1,234 km^2 to the nearest square kilometer

5 0
3 years ago
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