The theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
According to the given question.
A card is drawn from a shuffled standard deck.
Since, the total number of cards in a shuffled standard deck = 52
And, the total number of aces in a shuffled standard deck = 4
As, we know that "the theoretical probability of an event is the number of desired outcomes divided by all possible outcomes".
Therefore, the theoretical probabability of drawing an ace from a shuffled deck of playing cards
= 4/52
= 1/13
Hence, the theoretical probaility of drawing an ace from a shuffled deck of playing cards is 1/13.
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Answer:
x=11/8
Step-by-step explanation:
As a decimal is 1.375
Answer:
Not larger or smaller; the areas are the same
Step-by-step explanation:
Recall that the formula for the area of a triangle of base b and height h is
A = (1/2)(b)(h).
In the first case, h = 3 ft and b = 2.5 ft. This results in an area of 3.75 ft^2.
In the second case, h = 2.5 ft and b = 3 ft. The area is the same: 3.75 ft^2.
This is because A = (1/2)(b)(h) has the same value regardless of the order in which b and h are used as multipliers.
There is no difference in the areas of the two signs. The areas are the same.
Divide both sides by -2
two negatives make a positive and that's true so x = 16/2 so divide it
x = 8 because 2 x 8 = 16 and 2/16 = 8 so true.
Answer: x = 8.
If B is the midpoint of AC, that means that the distances from A to B and B to C are the same. The distance from A to B is 8x + 4, and the distance from B to C is 10x - 6, so we can set these two equivalent:
8x + 4 = 10x - 6
Solving for x:
4 = 2x - 6 (subtract 8x from both sides)
10 = 2x (add 6 to both sides)
5 = x (divide both sides by 2)
So, x = 5, which is the second option given.
