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3 years ago

10

A pet store currently has a total of 45 cats and dogs. There are 7 more cats than dogs. Find the number of cats and dogs in the

store. Write and solve a system of equations that represents the situation. Interpret the solution

1 answer:

dusya [7]3 years ago

8 0

45 dogs and 52 cats because 5+7=12 so 45+7=52

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Help.? geometry basics homework 2: segment addition postulate

Neporo4naja [7]

The value of x is 3 given that ST = 8x + 11 and TU = 12x-1

The point that bisects a line divides the line into two equal parts

If T is the midpoint of SU, the following are true:

ST = TU
ST + TU = SU

Given the following

ST = 8x + 11

TU = 12x-1

Since ST = TU

8x+11 = 12x-1

8x - 12x = -1 - 11

-4x = -12

x = 12/4

x = 3

Hence the value of x is 3 given that ST = 8x + 11 and TU = 12x-1

Learn more here: brainly.com/question/17204733

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2 years ago

Read 2 more answers

Problem1 The behavior of a physical system can be described by the following first order differential equation: dy/dt=2y +t^2

daser333 [38]

Answer:

$y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}$ .

Step-by-step explanation:

Using first order linear differential equation:

$\dfrac{\mathrm{d} y}{\mathrm{d} t} = 2y + t^2$

$\frac{\mathrm{d} y}{\mathrm{d} t} - 2y =t^2$

finding integrating factor:

I.F = $e^{\int -2dt}$

I.F = $e^{-2t}$

now,

$y = \dfrac{1}{IF}(\int t^2dt+ c )$

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$y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}$

hence the solution is

$y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}$

8 0

3 years ago

Sarah hopes to be 5 feet tall by her next birthday. Right now, she is 148 centimeters tall. how many more centimeter does Sarah

OlgaM077 [116]

Sarah needs 4.4 centimeters more to reach 5 feet before her next birthday.

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1 year ago

Read 2 more answers

Law of radicals

andrey2020 [161]

Answer:

1) $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

Step-by-step explanation:

1) $\sqrt{x^7}$

We know that $\sqrt{x}=x^{\frac{1}{2}$

So, $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}$

We know that $\sqrt[3]{x}=x^{\frac{1}{3}$

So, $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}$

We know that $\sqrt[5]{x}=x^{\frac{1}{5}$

So, $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}$

We know that $\sqrt[4]{x}=x^{\frac{1}{4}$

So, $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

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2 years ago

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Maksim231197 [3]

Answer:

A

Step-by-step explanation:

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2 years ago