Given:
Cost function c(x) = I0x+13
Profit Function p(x) = -0.3x² + 47x - 13
Find: revenue function r(x)
Solution:
To solve for the revenue function, simply add the cost and the profit function.
![(10x+13)+(-0.3x^2+47x-13)](https://tex.z-dn.net/?f=%2810x%2B13%29%2B%28-0.3x%5E2%2B47x-13%29)
Eliminate the parenthesis.
![10x+13-0.3x^2+47x-13](https://tex.z-dn.net/?f=10x%2B13-0.3x%5E2%2B47x-13)
Rearrange the terms according to their degree.
![-0.3x^2+47x+10x+13-13](https://tex.z-dn.net/?f=-0.3x%5E2%2B47x%2B10x%2B13-13)
Combine similar terms.
![-0.3x^2+57x](https://tex.z-dn.net/?f=-0.3x%5E2%2B57x)
Therefore, the revenue function r(x) is -0.3x² + 57x or by commutative property, the revenue function R(x) = 57x - 0.3x². (Option 3).
When x=0 y=50 when y=0 x=+\-5. -x^2 makes the parabola open downward y(x)=2x^2+50;y(3)=2*9+50=32
9514 1404 393
Answer:
∠GDH = ∠GHD = 50°
Step-by-step explanation:
Angles FGD and EDG are alternate interior angles, so are congruent. That means angle EDG is 100°. The angle sum theorem tells us ...
∠EDG = ∠EDH +∠HDG
100° = 50° +∠HDG
50° = ∠HDG
You can find the measure of ∠DHG a couple of different ways. It is an alternate interior angle congruent to ∠EDH, so is 50°. It is one of two remote interior angles that have a sum equal to the exterior angle FGD, so is ...
∠DHG = ∠FGD -∠HDG = 100° -50° = 50°
So, angles DHG and HGD both have measures of 50°. When a triangle has two angles with the same measure, it is an isosceles triangle.
Answer:
36
Step-by-step explanation:
"Two more" = + 2
"quotient of a number and 6" = n/6
"equal to 8" = = 8
Set the equation:
n/6 + 2 = 8
Isolate the variable n. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 2 from both sides.
n/6 + 2 (-2) = 8 (-2)
n/6 = 8 - 2
n/6 = 6
Isolate the variable n. Multiply 6 to both sides.
(n/6)(6) = (6)(6)
n = 6 * 6
n = 36
36 is your answer.
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The answer is c you multiply the base (5)(5)=25 and add the exponents 4+8=12 so the answer is 25^12