<span>C and B are *candidates* for being the correct solution
because f(2) = 4 for both.
</span>
A is the correct solution because f(3)=6
The answer to this question is D
Answer:
<em> There are 7 bales of 100 pounds and 8 bales of 150 pounds hale</em>
Step-by-step explanation:
Let the amount of bale of 100 pounds be x and the bale of hale of 150pounds be y
If fifteen bales of hale were loaded into a truck, then x+y = 15 ... 1
Also if some of the bales weight 150 pounds, and some weighed 100 pounds with total weight of pounds to be 1900 pounds, then mathematically;
150y + 100x = 1900
Dividing through by 100;
1.5y+x = 19 ..... 2
Solving equation 1 and 2 simultaneously;
x+y = 15 ... 1
1.5y+x = 19 .... 2
Subtracting 1 from 2
y-1.5y = 15-19
-0.5y = -4
Divide both sides by 0.5
-0.5y/-0.5 = -4/-0.5
y = 8
Substituting y = 8 into equation 1, we will have;
x+y = 15
x+8 = 15
x = 15-8
x = 7
<em>Hence there are 7 bales of 100 pounds and 8 bales of 150 pounds hale</em>
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