If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
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y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4 </span>← to the nearest tenth<span>
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Answer:
Step-by-step explanation:
what points do you want me to plot?
Answer:
Step-by-step explanation:
Answer:
(5x + 40), (7x + 8), (10x)
Step-by-step explanation:
Ok, I'm not completely sure, I'm taking a bullet here. But lemme know what you get
Answer:
Step-by-step explanation:
Given the expression
3x + 2 = 4x + 5
1. The smaller coefficient of x is 3
to remove the smaller coefficient
we need to add - 3x to both sides
3x +2 + (-3x) = 4x +5 (-3x)
3x + 2 - 3x = 4x + 5 - 3x
Collecting like terms we have
3x-3x+2= 4x-3x+5
2 = x+ 5
2. The constant on the right side is
5,to remove the constant from the right side of the equation we need to add - 5 to both sides
3x + 2+ (- 5) = 4x + 5 +(-5)
3x+ 2-5 =4x +5-5
3x-3 = 4x
