There are two types of aymptotes; horizontal and vertical asymptote. To find asymptotes of a function, you first must know the domain and range of the given function. Let's say the function is:
Horizontal Asymptote:
To find this asymptote, we have to look at the domain (or the denominator). The domain will be: x such that x is not = to 2. This is because the denominator is x-2, and if you substitute x with 2 it will be 2-2=0. But, anything divided by 0 is undefined. To find the asymptote,you take the denominator itself;
Vertical Asymptote:
To find this asymptote, we have to look at the range of the function by finding the inverse of the given function. From the given function;
We now write y instead of f(x).
Now, interchange the variables.
Now,make y the subject in order to get the inverse of the function.
The range will be x is not equal to 1, since the result will be 0, and,
Therefore, the asymptote will be obtained by looking at the denominator of the inverse of the function; i.e.
Now, replace x with letter y.
Therefore, the asymptotes have been obtained.
I hope you understand the concept.
Thank you;
kaloliavivek
Horizontal Asymptote:
To find this asymptote, we have to look at the domain (or the denominator). The domain will be: x such that x is not = to 2. This is because the denominator is x-2, and if you substitute x with 2 it will be 2-2=0. But, anything divided by 0 is undefined. To find the asymptote,you take the denominator itself;
Vertical Asymptote:
To find this asymptote, we have to look at the range of the function by finding the inverse of the given function. From the given function;
We now write y instead of f(x).
Now, interchange the variables.
Now,make y the subject in order to get the inverse of the function.
The range will be x is not equal to 1, since the result will be 0, and,
Therefore, the asymptote will be obtained by looking at the denominator of the inverse of the function; i.e.
Now, replace x with letter y.
Therefore, the asymptotes have been obtained.
I hope you understand the concept.
Thank you;
kaloliavivek