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Zepler [3.9K]
3 years ago
5

Please help!!!!

Mathematics
2 answers:
N76 [4]3 years ago
7 0

Answer:

9 + X = 16

Step-by-step explanation:

Given parameters:

   Number of students on the roll  = 9

   

Unknown:

The equation representing the class roster  = ?

Solution:

Let the number of additional students that joined the class = x

  Carol's class roster:

     New number of students = number of students + additional students

          16  = 9 + x

The solution of the problem is 9 + x = 16

natita [175]3 years ago
5 0
The last one, 9+x=16
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Multiply the following 11 x square Y and 2 x square y square
yaroslaw [1]

Answer:

22 x^4y^3

Step-by-step explanation:

11x^2y\times 2x^2y^2\\

by multiplying

=11 \times 2 \times x^2 \timesx^2 \times y \times \times y^2\\=22 \times x^{2+2}y^{1+2}\\=22 x^4y^3

3 0
4 years ago
The sum of 13 divided by a number and that number divided by 13
7nadin3 [17]
Sum means add

the number is x

13 divided by a number is 13/x
the number divided by the number is x/13


so
\frac{13}{x}+\frac{x}{13}
also can be simplified to
\frac{169}{13x}+\frac{x^2}{13x} or
\frac{x62+169}{13x}



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5 0
3 years ago
Evaluate the summation of negative 2 n minus 3, from n equals 2 to 10..
Alisiya [41]
\bf \sum\limits_{n=2}^{10}~-2n-3

so, let's first change the bounds from 1 to 9, so we'll be dropping the indices by 1, in order to do the variable "n".

however, let's use a variable hmmm say "k", where "k" is the value of "n" beginning at 1, thus k = n - 1.

however, if k = n - 1, then k + 1 = n.  So let's use those fellows then,

\bf \sum\limits_{n=2}^{10}~-2n-3\qquad 
\begin{cases}
k=n-1\\
k+1=n
\end{cases}\implies \sum\limits_{k=1}^{9}~-2\stackrel{n}{(k+1)}-3
\\\\\\
\sum\limits_{k=1}^{9}~-2k-2-3\implies \sum\limits_{k=1}^{9}~-2k-5\implies \sum\limits_{k=1}^{9}~-2k-\sum\limits_{k=1}^{9}~5
\\\\\\
-2\sum\limits_{k=1}^{9}~k-\sum\limits_{k=1}^{9}~5\implies -2\left( \cfrac{9(9+1)}{2} \right)\qquad -\qquad (9\cdot 5)
\\\\\\
-2(45)-45\implies -90-45\implies -135
5 0
3 years ago
How to change 611/17 to improper fractions
Annette [7]
This is the answer ....

3 0
4 years ago
Read 2 more answers
1. (4x2 – 2x+8)+(x² + 3x - 2)
krek1111 [17]

Answer:

I   simplify  it and got 5x^2+z+6

Step-by-step explanation:

(4x2 – 2x+8)+(x² + 3x - 2)v=5x^2+z+6

4 0
3 years ago
Read 2 more answers
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