Answer:
1.11
Step-by-step explanation:
1.03+0.08=1.11
Answer:
yes
Step-by-step explanation:
The line intersects each parabola in one point, so is tangent to both.
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For the first parabola, the point of intersection is ...
y^2 = 4(-y-1)
y^2 +4y +4 = 0
(y+2)^2 = 0
y = -2 . . . . . . . . one solution only
x = -(-2)-1 = 1
The point of intersection is (1, -2).
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For the second parabola, the equation is the same, but with x and y interchanged:
x^2 = 4(-x-1)
(x +2)^2 = 0
x = -2, y = 1 . . . . . one point of intersection only
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If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.
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Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.
Answer:
(-1,0) and (5,0)
Step-by-step explanation:
The roots are the points where the y-value is 0 and the point lies exactly on the x-axis.
(blank,0)
In this parabola, the points that are exactly on the x-axis is (-1,0) and (5,0)
We take the value of F in the inequality by taking the inequalities in group. Let the first group be:
(1) -20 ≤ 59(F - 32)
Then, the second group would be,
(2) 59(F - 32) ≤ - 15
Calculating for the values of F,
(1) -20 ≤ 59F - 1888
1888 - 20 ≤ 59F
1868 ≤ 59F
F ≥ 31.66
(2) (59)(F - 32) ≤ - 15
59F - 1888 ≤ -15
59F ≤ 1873
F ≤ 31.75
The values of F are therefore,
31.66 ≤ F ≤ 31.75
Answer:
A) x=6
Step-by-step explanation:
6.5^2-2.5^2=x^2
42.25-6.25=x^2=36
x=6