If the question is to find the slope-intercept form of both lines, here's the answer:
Both lines pass through the point (-3,-4), so we can use these coordinates in both equations. The slope-intercept form is represented by y=mx+b, with m the slope, b the intersection of the line with Y'Y for x=0, y and x the coordinates of a point.
Let's first apply all these for the first line, with a slope of 4.
y = mx + b
y=-3; x=-4; m=4. All we need to do is find b.
-3 = 4(-4) + b
-3 = -16 + b
b=13
So the equation of the first line is y= 4x + 13.
Now, we'll do the same thing but for the second line:
y=-3; x=-4; m=-1/4, and we need to find b.
-3 = (-1/4)(-4) + b
-3 = 1 + b
b= -4
So the equation of the second line is y=(-1/4)x - 4
Hope this Helps! :)
Answer:
y - 3 = 2/3(x + 2)
Step-by-step explanation:
slope = 2/3
point-slope form --> y - y1 = m(x - x1)
y - 3 = 2/3(x - -2)
y - 3 = 2/3(x + 2)
point slope form of the line is y - 3 = 2/3(x + 2)
Answer:
AB = 5
Step-by-step explanation:
Since the triangle is isosceles then the legs are congruent, that is
BC = BA, substitute values
5x - 10 = 3x - 4 ( subtract 3x from both sides )
2x - 10 = - 4 ( add 10 to both sides )
2x = 6 ( divide both sides by 2 )
x = 3
Thus
AB = 3x - 4 = 3(3) - 4 = 9 - 4 = 5
